php - 如何在php中的另一个多键/值数组中查找多键/值对组合数组

Question

我有一个数组列表(对于这个例子，我使用的是 Google 的颜色)。我希望能够搜索多个键/值对，如果找到数组对则返回 true，否则返回 false。

输入如下颜色和lenscolor对:这个值是动态的，来自动态下拉列表 大批 ( [颜色] => Tokyo Tortoise,matte Gold & Green [LensColor] => 绿色 )

在此数组中搜索上面的颜色和透镜颜色对这个值是动态的，来自xml文件(转换成数组) 大批 ( [0] => 阵列 ( [颜色] => 羽毛卡梅尔色、哑光青铜色和棕色 [LensColor] => 棕色 )

    [1] => Array
        (
            [Color] => Matte Black,matte Black & Smoke
            [LensColor] => Smoke
        )

    [2] => Array
        (
            [Color] => Tokyo Tortoise,matte Gold & Green
            [LensColor] => Green
        )
    [3] => Array
        (
            [Color] => Matte Black,matte Black & Smoke
            [LensColor] => Green
        )
    [4] => Array
        (
            [Color] => Feathered Carmel,matte Gunmetal & Brown
            [LensColor] => Green
        )
    [5] => Array
        (
            [Color] => Feathered Carmel,matte Gunmetal & Brown
            [LensColor] => Smoke
        )

)

Answer 1

这个想法很简单:

    $arr =Array(Array
    (
        "Color" => "Matte Black,matte Black & Smoke",
        "LensColor" => "Smoke"
    ),

    Array(
        "Color" => "Tokyo Tortoise,matte Gold & Green",
        "LensColor" => "Green"
    ),
    Array(
        "Color" => "Matte Black,matte Black & Smoke",
        "LensColor" => "Green"
    ),
    Array(
        "Color" => "Feathered Carmel,matte Gunmetal & Brown",
        "LensColor" => "Green"
    ),
    Array(
        "Color" => "Feathered Carmel,matte Gunmetal & Brown",
        "LensColor" => "Smoke"
    )
            );
$founded = false;
$Color ="Tokyo Tortoise,matte Gold & Green";
$LensColor="Green";
echo $Color;
for ($i=0; $i<count($arr);$i++){

if($arr[$i]['Color']==$Color &&  $arr[$i]['LensColor']==$LensColor){
$founded=true;
break;
}
}
echo var_dump($founded);

它可以使更复杂。