php - 评论解析器的示例代码

Question

任何人都知道用于解析用户提交的评论的任何示例 php(最好是 codeigniter)代码。要删除脏话和 HTML 标签等？

Answer 1

尝试 strip_tags摆脱任何提交的 html。您可以使用 htmlspecialchars如果您只是想确保评论中不显示任何 html，则转义标签 - 根据 Matchu 的示例，与 strip_tags 相比，它会产生更少的意外影响。

关于单词过滤，看你想深入到什么程度，网上有很多例子，来自simple至 complex .这是 Jake Olefsky 示例中的代码(之前链接的简单示例):

<?
//This is totally free to use by anyone for any purpose.

// BadWordFilter
// This function does all the work. If $replace is 1 it will replace all bad words
// with the wildcard replacements.  If $replace is 0 it will not replace anything.
// In either case, it will return 1 if it found bad words or 0 otherwise.
// Be sure to fill the $bads array with the bad words you want filtered.
function BadWordFilter(&$text, $replace)
{
    //fill this array with the bad words you want to filter and their replacements
    $bads = array (
        array("butt","b***"),
        array("poop","p***"),
        array("crap","c***")
    );

    if($replace==1) {                               //we are replacing
        $remember = $text;

        for($i=0;$i<sizeof($bads);$i++) {           //go through each bad word
            $text = eregi_replace($bads[$i][0],$bads[$i][5],$text); //replace it
        }

        if($remember!=$text) return 1;              //if there are any changes, return 1

    } else {                                        //we are just checking

        for($i=0;$i<sizeof($bads);$i++) {           //go through each bad word
            if(eregi($bads[$i][0],$text)) return 1; //if we find any, return 1
        }   

    }
}

//this will replace all bad words with their replacements. $any is 1 if it found any
$any = BadWordFilter($wordsToFilter,1); 

//this will not repace any bad words. $any is 1 if it found any
$any = BadWordFilter($wordsToFilter,0); 

?>

更多这样的例子可以是found easily在网络上。