php - 阻止 Laravel 在异常中包含跟踪

Question

我有自己的异常扩展，调用时我希望它向浏览器输出一条消息。然而，当我抛出这个异常时，捕获它并输出消息但消息是一个痕迹。

这是我的 global.php:

class ApiException extends Exception {}
App::error(function(ApiException $ex){
    dd($ex->getMessage());  
});

我的代码片段:

try {
    if (!Input::get('password')) {
        throw new Exception('Password not set');
    }
    if (User::all()->count()) {
        throw new Exception('User already exists');
    }
    Artisan::call('db:seed', [
        '--class' => 'VerifyUserSeeder'
    ]);
    $User = \Toddish\Verify\Models\User::find(1);
    $User->password = Input::get('password');
    $User->save();
} catch (Exception $ex) {
    throw new ApiException($ex);
}

输出到浏览器:

exception 'Exception' with message 'Password not set' in /Users/kevin/Documents/Web/app/controllers/Settings/SetupController.php:8 Stack trace: #0 [internal function]: SetupController->setupPassword() 1 /Users/kevin/Documents/Web/vendor/laravel/framework/src/Illuminate/Routing/Controller.php(231): call_user_func_array(Array, Array) #2 .......

Answer 1

您能解释一下为什么要抛出一般异常、捕获它们然后再次抛出新异常吗？

为什么不直接抛出 ApiException 呢？

if (!Input::get('password')) {
    throw new ApiException('Password not set');
}
if (User::all()->count()) {
    throw new ApiException('User already exists');
}
Artisan::call('db:seed', [
    '--class' => 'VerifyUserSeeder'
]);
$User = \Toddish\Verify\Models\User::find(1);
$User->password = Input::get('password');
$User->save();