php - 如何使用php计算到下一个生日的天数

Question

我有 2 个出生日期输入字段。然后我想计算每个人到下一个生日的天数，以及输入的两个日期之间的差异以确定谁年纪大。我的语法是否合乎逻辑/我哪里出错了？

<form>
  John's Birthday (YYYY-MM-DD):
  <input type=text name=jhbd value=0><br> Jake's Birthday (YYYY-MM-DD):
  <input type=text name=jkbd value=0><br>
  <input type=submit>
</form>

$john_bd = $_POST['jhbd'];
$jake_bd = $_POST['jkbd'];

$today = date("Y/m/d");
$interval_jh = $john_bd ->diff($today);
$interval_jk = $jake_bd ->diff($today);

echo "There are".$interval_jh->days."days until John's birthday ";
echo "There are".$interval_jk->days."days until Jake's birthday ";

if ($john_bd > $jake_bd) {
   echo "John is older";
} else if ($jake_bd > $john_bd) {
   echo "Jake is older";
} else {
   echo "Both Jake and John are twins!";
}

Answer 1

您需要先转换它们。

 $today = time(); 
 $your_date = strtotime($john_bd);
 $datediff = $now - $john_bd;
 echo floor($datediff/(60*60*24));

可能对你有帮助