php - strtotime() 期望参数 1 为字符串，数组给定

Question

查看 result_array 时出错，请帮助我获取此 View 。

型号:

public function raw_attendance_Status() {
        $this->db->distinct();
        $this->db->select('attnDate');
        $this->db->from('tbl_attendance');
        $this->db->order_by('attnDate');
        $query = $this->db->get();
        return $query->result_array();
    }

Controller :

public function rawAttendance(){
        $data['Dates'] = $this->AttendanceModel->raw_attendance_Status();
        $this->load->view('attendance/rawAttendance', $data);
    }

查看:

foreach ($Dates as $k=>$v) {
        $dates[$k] = date('d-M-Y', strtotime($v));
    }
    $heads = "<table border='1'>\n";
    $heads .= "<tr><th>TraineeID</th><th>" . join('</th><th>', $dates) . "</th></tr>\n";
$tdata .= "</table\n";

$dates 变量输出:array(13) { [0]=> array(1) { ["attnDate"]=> string(10) "2015-11-25"} [1]=> array(1) { ["attnDate "]=> string(10) "2015-11-29"} [2]=> array(1) { ["attnDate"]=> string(10) "2015-11-30"} [3]=> array(1) { ["attnDate"]=> string(10) "2015-12-01"} [4]=> array(1) { ["attnDate"]=> string(10) "2015-12- 02"} [5]=> array(1) { ["attnDate"]=> string(10) "2015-12-03"} [6]=> array(1) { ["attnDate"]=> string (10) "2015-12-05"} [7]=> array(1) { ["attnDate"]=> string(10) "2015-12-06"} [8]=> array(1) { ["attnDate"]=> string(10) "2015-12-07"} [9]=> array(1) { ["attnDate"]=> string(10) "2015-12-08"} [10 ]=> array(1) { ["attnDate"]=> string(10) "2015-12-09"} [11]=> array(1) { ["attnDate"]=> string(10) "2015 -12-10"} [12]=> array(1) { ["attnDate"]=> string(10) "2015-12-12"} }

Answer 1

由于您的结果以多维数组形式返回，因此使用:

$dates[] = date('d-M-Y', strtotime($v['attnDate']));

代替:

$dates[] = date('d-M-Y', strtotime($v));