php - Guzzle PUT 请求身份验证错误

Question

我有以下代码使用来自另一个系统的 API 保存内容。我已经添加了凭据，但它显示了错误的凭据错误。它在 postman 中完美运行。

    $client = new GuzzleHttpClient();
try {
  $request = new \GuzzleHttp\Psr7\Request('PUT', config('cms.api.backend') .'/products/'. $nid,
    [
      'auth' => [config('cms.api.user'), config('cms.api.password')],
      'form_params' => [
        'copywrite' => Input::get('copywrite'),
        'status' => $status
      ],
  ]);
  $promise = $client->sendAsync($request)->then(function ($response) {});
  $promise->wait();
}
catch (RequestException $e) {
  $this->logHttpError($e->getResponse()->getStatusCode(), $e->getResponse()->getBody(true));
}

上面的代码有什么问题吗？

以下是postman导出的代码

$request = new HttpRequest();
$request->setUrl('http://mybackend/api/products/74371');
$request->setMethod(HTTP_METH_PUT);

$request->setHeaders(array(
  'postman-token' => 'e0ddcaea-4787-b2c5-0c52-9aaee860ceac',
  'cache-control' => 'no-cache',
  'authorization' => 'Basic authenticationcode',
  'content-type' => 'application/x-www-form-urlencoded'
));

$request->setContentType('application/x-www-form-urlencoded');
$request->setPostFields(array(
  'copywrite' => 'date to be saved'
));

try {
  $response = $request->send();

  echo $response->getBody();
} catch (HttpException $ex) {
  echo $ex;
}

Answer 1

\GuzzleHttp\Psr7\Request 中的第三个参数仅用于 header 数组，因此您不会以这种方式发送请求正文(第 4 个参数)。最简单的方法是将此数组作为第二个参数传递给 sendAsync() 方法。它会识别它们并且 form_params 选项将被解析为 Content-Type: application/x-www-form-urlencoded header 并为您的请求创建一个有效的流(它使用http_build_query() 函数(如果您想直接在请求构造函数中执行):

$request = new \GuzzleHttp\Psr7\Request('PUT', config('cms.api.backend') .'/products/'. $nid);
$options = [
    'auth' => [config('cms.api.user'), config('cms.api.password')],
    'form_params' => [
        'copywrite' => Input::get('copywrite'),
        'status' => $status
    ],
];


$promise = $client->sendAsync($request, $options)->then(function ($response) {});
$promise->wait();