php - 如何从php中的url获取图像的大小？

Question

我一直在尝试从 url 获取图像的大小，但它不起作用。谁能帮我？

这是代码:

$imagesize = getimagesize('https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0');
echo $imagesize;

Answer 1

您没有得到图像 https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0在这个网址中

你需要得到的是图片地址，就是这个 https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/EJrFv4kEGLgCIAIoAg/cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0?dl=0&size=1280x960&size_mode=3

代码

$imagesize = getimagesize('https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/EJrFv4kEGLgCIAIoAg/cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0?dl=0&size=1280x960&size_mode=3');
print_r($imagesize);

结果

Array
(
    [0] => 1000
    [1] => 750
    [2] => 2
    [3] => width="1000" height="750"
    [bits] => 8
    [channels] => 3
    [mime] => image/jpeg
)

也可以引用这个Dropbox get public url of the file after upload

只需更改:

https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0

到

https://dl.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg

只需将 www 替换为 dl 并删除 ?dl=0