PHP过滤1个url的数组

Question

我制作了一个脚本，该脚本创建了一个从页面中抓取的 url 数组，我想仅针对 1 个特定的 url 过滤该数组。该数组目前看起来像这样:

Array
(
    [0] => index.jsp
    [1] => feedback.jsp
    [2] => faq.jsp
    [3] => donate.jsp
    [4] => contact.jsp
    [5] => widgetmaker.jsp
    [11] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [12] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [13] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [14] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [15] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
)

我想要它做的是获取“http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php”之一链接。我该怎么做？

Answer 1

如果我理解正确，您只想获得完全限定的(绝对)URL:

$filtered = array_filter($urls, function($url) {
    if (strpos($url, 'http://') === 0) return true;
    return false;
});

如果您同时需要 http 和 https url:

$filtered = array_filter($urls, function($url) {
    if (preg_match('#^https?://#', $url)) return true;
    return false;
});

如果您只想要完全匹配:

$filtered = array_filter($urls, function($url) {
    if ($url == 'http://full/url/goes/here') return true;
    return false;
});

如果你只想得到第一个那么:

$url = $filtered[0];