frameworks - NGINX 配置。带有 PATHINFO 404 的 PHP 框架

Question

我平时用apache，想试试NGINX。

我已将它安装在我的 ubuntu 开发机器上，并设置和开发了一些不同的框架和站点(codeigniter、symfony、laravel 等)。

我遇到的问题是只有以 .php 结尾的路径才有效。如果我尝试 index.php/welcome/index 它只是 404s 而不是加载 index.php。

我试过将 cgi.fix_pathinfo 设置为 1 和 0。

这是我当前的(许多尝试过的)站点配置。

server {
listen   80; ## listen for ipv4; this line is default and implied
#listen   [::]:80 default_server ipv6only=on; ## listen for ipv6

root /my/path;
index index.php index.html;

# Make site accessible from http://localhost/
server_name localhost;

#error_page 404 /404.html;

# redirect server error pages to the static page /50x.html
#
#error_page 500 502 503 504 /50x.html;
#location = /50x.html {
#   root /usr/share/nginx/www;
#}

location ~ \.php$ {
    try_files $uri =404;

    # Fix for server variables that behave differently under nginx/php-fpm than typically expected
    fastcgi_split_path_info ^(.+\.php)(/.+)$;
    # Include the standard fastcgi_params file included with nginx
    include fastcgi_params;
    fastcgi_param  PATH_INFO        $fastcgi_path_info;
    fastcgi_index index.php;
    # Override the SCRIPT_FILENAME variable set by fastcgi_params
    fastcgi_param  SCRIPT_FILENAME  $document_root$fastcgi_script_name;
    # Pass to upstream PHP-FPM; This must match whatever you name your upstream connection
    fastcgi_pass unix:/var/run/php5-fpm.sock;
}


location / {
    # First attempt to serve request as file, then
    # as directory, then fall back to displaying a 404.
    try_files $uri $uri/ =404;
    # Uncomment to enable naxsi on this location
    # include /etc/nginx/naxsi.rules
}

# deny access to .htaccess files, if Apache's document root
# concurs with nginx's one
#
location ~ /\.ht {
    deny all;
}
}

Answer 1

我更愿意使用以下 nginx 配置结构。它更干净:

location / {
  try_files $uri $uri/ @phpsite;
}

location @phpsite {
  include fastcgi_params;
  ... other fast_cgi directives
}

可以在流行的 silex 项目中找到更复杂的设置:http://silex.sensiolabs.org/doc/web_servers.html#nginx .

我在原始配置文件中看到 2 个问题:

location ~ \.php$ {
    try_files $uri =404;
    ...
}

1. 在正则表达式中，'$' 表示匹配字符串的末尾。因此，如 prodigitalson 的评论所述，它失败了。
2. 上面的 fast_cgi 位置 block 中的 try_files 指令不应该存在，因为该位置 block 应该由 php 单独处理。删除那条线会更干净。