php - 如何不向浏览器输出图像？

Question

我的代码:

ob_start();
imagejpeg($resource, NULL, 75);  break; // best quality
$resource = ob_get_contents();
ob_end_flush();

我仅将 imagejpeg() 用于输出缓冲，不需要输出到浏览器。有什么想法吗？

Answer 1

让我们试着分析一下你在那里做了什么:

// start output buffering
ob_start();
// output the image - since ob is on: buffer it
imagejpeg($resource, NULL, 75);
// this break could be a problem - if this is in a control structure, remove it
break;
// save the ob in $resouce
$resource = ob_get_contents();

// here is the image now in $resource AND in the output buffer since you didn't clean it (the ob)

// end ob and flush (= send the ob)
ob_end_flush();

所以你做错的是，你 1) 没有 clean输出缓冲区和/或 2) flushed对象。

我的建议是使用 ob_get_clean ( reference )(简单示例):

$im = imagecreatetruecolor(120, 20);
ob_start();
imagejpeg($im);
$var = ob_get_clean();