php - 为什么我在 View 中的显示 Controller 数组中出现错误 undefined variable ？

Question

我的 Controller :

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class VerifyAppointment extends CI_Controller {

    function __construct()
    {
        parent::__construct();


        $this->load->model('appointment_model','',TRUE);

    }

    function index()
    {
        $this->load->library('form_validation');

        $this->form_validation->set_rules('rdatetimepicker', 'Appointment date', 'trim|required|xss_clean');

        if($this->form_validation->run() == FALSE)
        {
            $this->load->view("pages/appointment");
        }
        else
        {
            $this->appointment_model->insert();
            $data['posts'] = "hih";

            $this->load->view('pages/appointment',$data);
        }

    }

}

我的看法:

<?php

    echo $posts;
?>

Answer 1

你收到错误是因为当你初始化 $data['posts']=""; 根据您的编码风格在开始或每个 if 条件中

 function index()
        {
            $this->load->library('form_validation');

        $this->form_validation->set_rules('rdatetimepicker', 'Appointment date', 'trim|required|xss_clean');

        if($this->form_validation->run() == FALSE)
        {
           $data['posts']="";  //declare posts here              
          $this->load->view('pages/appointment',$data);

        }
        else
        {
            $this->appointment_model->insert();
            $data['posts'] = "hih";

            $this->load->view('pages/appointment',$data);
        }

    }

或者你可以在 View 之前检查数组，像这样；如果你不想改变你的 Controller

<?php
    if(isset($posts))
    echo $posts;
?>