当 Echo 不存在时 PHP 服务器错误 500？

Question

当我在某个位置添加回显时，我的 php 代码工作正常，但是当我删除简单的 echo "hello"; 行时，它不会加载 php 页面，它只显示服务器错误500.

以下代码有效:

require 'steam.php';
    $steam = new steam();
    $api = "FC1D74A835829EB99A571235A499638A";
    $query = 'ari9';

    $communityID            =   $steam->getID($query, $api);
    $userInfo               =   $steam->getUserInfo($communityID, $api);

    echo "hello";

    $info = array(
        'communityID'   =>  $communityID,
        'steamID'       =>  $steam->$convertToSteamID($communityID),
        'personaname'   =>  $userInfo['personaname'],
        'profileurl'    =>  $userInfo['profileurl'],
        'lastlogoff'    =>  $userInfo['lastlogoff'],
    );

    foreach ($info as $key => $value) {
        if (strlen($value)===0) {
            $info[$key] = false;
        }
        echo $key." -> ".$value."<br>";
    }
    echo json_encode($info);

下面的代码不有效:

require 'steam.php';
    $steam = new steam();
    $api = "FC1D74A835829EB99A571235A499638A";
    $query = 'ari9';

    $communityID            =   $steam->getID($query, $api);
    $userInfo               =   $steam->getUserInfo($communityID, $api);

    $info = array(
        'communityID'   =>  $communityID,
        'steamID'       =>  $steam->$convertToSteamID($communityID),
        'personaname'   =>  $userInfo['personaname'],
        'profileurl'    =>  $userInfo['profileurl'],
        'lastlogoff'    =>  $userInfo['lastlogoff'],
    );

    foreach ($info as $key => $value) {
        if (strlen($value)===0) {
            $info[$key] = false;
        }
        echo $key." -> ".$value."<br>";
    }
    echo json_encode($info);

并且以下代码不有效:

require 'steam.php';
    $steam = new steam();
    $api = "FC1D74A835829EB99A571235A499638A";
    $query = 'ari9';

    $communityID            =   $steam->getID($query, $api);
    $userInfo               =   $steam->getUserInfo($communityID, $api);

    $info = array(
        'communityID'   =>  $communityID,
        'steamID'       =>  $steam->$convertToSteamID($communityID),
        'personaname'   =>  $userInfo['personaname'],
        'profileurl'    =>  $userInfo['profileurl'],
        'lastlogoff'    =>  $userInfo['lastlogoff'],
    );

    foreach ($info as $key => $value) {
        if (strlen($value)===0) {
            $info[$key] = false;
        }
        echo $key." -> ".$value."<br>";
    }
    echo json_encode($info);

    echo "Hello";

第一段代码在第 9 行有回显，第二段代码与第一段相同，除了第 9 行的回显被删除。我对此感到困惑。

Answer 1

问题是这个 $steam->$convertToSteamID 正在寻找一个函数，该函数的名称与变量值是什么有关。当没有 echo 时你得到 500 的原因是因为当你发送服务于 200 的 echo 时。你的日志中应该有事件显示错误。一个页面上不能有 2 个状态代码。

所以只需将您的函数调用更改为:

$steam->convertToSteamID

你应该没问题。