javascript - datepicker 显示基于年份的日期 - JQuery

Question

我尝试根据选定的下拉列表加载当前年份和上一年(2017、2018)的日期范围。但是我的日期选择器只显示首先选择的年份。

I can show the years which is first selected. Example First selected year- 2017 means show the 2017 calender Second change selected year- 2018 means show the 2017 calender

HTML 代码:

 <?php $year = date('Y'); ?>
 <select name="hyear" id="hyear" data-placeholder="Select Year"  class="form-control chosen-select">                                       
     <option value="<?php echo $year ?>"><?php echo $year ?></option>      
     <option value="<?php echo ++$year ?>"><?php echo $year ?></option>                                            
 </select>

脚本代码:

 function updateDatePic(mindate, maxdate)
    {
        $('#hdate').datepick({
            minDate: mindate,
            maxDate: maxdate,
            onSelect: function () {

            }
        });
    }

    $('#hyear').change(function () {
        var year = $.trim($("#hyear").val());
        var mindate = '01/01/' + year;
        var maxdate = '12/31/' + year;        
        alert("mindate="+mindate+"...maxdate="+maxdate);        
        updateDatePic(mindate, maxdate);
    });

请指教!

Answer 1

请使用此代码:

$( "#hdate" ).datepicker({   
    dateFormat: 'dd/mm/yy',
    changeMonth: true,
    changeYear: true,
    yearRange: '2017:2018'
});