php - 从字符串中获取特定字符串？

Question

我一直在尝试从字符串中获取特定的字符串，例如从下面的这个字符串中

Scale Lengths

4 string model - E A D G
5 string model - B E A D G
6 string model - B E A D G C

B   37″

我想要这部分

4 string model - E A D G
5 string model - B E A D G
6 string model - B E A D G C

我的代码如下，我得到了正确的答案

<?php
$str = 'Scale Lengths

4 string model - E A D G
5 string model - B E A D G
6 string model - B E A D G C

B
37″';

echo getBetween($str,'Scale Lengths','37″');
function getBetween($content,$start,$end){
  $r = explode($start, $content);
  if (isset($r[1])){
      $r = explode($end, $r[1]);
      return $r[0];
  }
  return '';
}
 ?>

问题: 我的问题是我上面的代码只针对这个字符串的静态类型。例如，如果我们将 37″ 更改为 28″ 或将此数字之前的 B 更改为 C 它将开始给出错误的答案。

Answer 1

尝试像这样更改您的代码:

<?php
$str = 'Scale Lengths

4 string model - E A D G
5 string model - B E A D G
6 string model - B E A D G C

B
37″';

$get_occurence=explode(" ",$str);
$split=preg_replace('/\s+/', '', end($get_occurence));
$split=preg_replace('/^[a-zA-Z]+/', '', $split);
$getBetween=getBetween($str,'Scale Lengths',$split);
$getLength=strlen($getBetween);
$getString=substr($getBetween,0,$getLength-3);

echo $getString;
function getBetween($content,$start,$end){
$r = explode($start, $content);
if (isset($r[1])){
  $r = explode($end, $r[1]);
  return $r[0];
}
return '';
}


?>

我已经编辑了一些代码，所以你可以用任何你想要的动态替换 B 字符串。

<?php
$str = 'Scale Lengths

4 string model - E A D G
5 string model - B E A D G
6 string model - B E A D G C

B
37″';

$get_occurence=explode(" ",$str);
$split=preg_replace('/\s+/', '', end($get_occurence));
$split=preg_replace('/^[a-zA-Z]+/', '', $split);
$split_integer=preg_replace('/\s+/', '', end($get_occurence));
$split_integer=preg_replace('/[^a-zA-Z.]*/', '', $split_integer);
$getBetween=getBetween($str,'Scale Lengths',$split);
$getLength=strlen($getBetween);

$getString=substr($getBetween,0,$getLength-(strlen($split_integer)+1));

echo $getString;
function getBetween($content,$start,$end){
$r = explode($start, $content);
if (isset($r[1])){
  $r = explode($end, $r[1]);
  return $r[0];
}
return '';
}


?>

希望对你有帮助。