php - 删除关联数组中的父元素

Question

问题:

我想用条件删除数组的父元素。

输入

$myArray = array (
    0 =>
    array (
      'ulStatic' =>
      array (
        0 =>
        array (
          'day' => '2019-03-30 18:30:00',
          'id' => '7',
          'origin' => 'intentions',
        ),
      ),
      'ulDynamic' =>
      array (
        0 =>
        array (
          'day' => '2019-03-30 18:30:00',
          'id' => '5',
          'origin' => 'intentions',
        ),
      ),
      'ulCreatedDynamic' =>
      array (
      ),
    ),
    1 =>
    array (
      'ulStatic' =>
      array (
        0 =>
        array (
          'day' => '2019-03-31 09:30:00',
          'id' => '8',
          'origin' => 'intentions',
        ),
      ),
      'ulDynamic' =>
      array (
      ),
      'ulCreatedDynamic' =>
      array (
      ),
    ),
    2 =>
    array (
      'ulStatic' =>
      array (
      ),
      'ulDynamic' =>
      array (
      ),
      'ulCreatedDynamic' =>
      array (
        0 =>
        array (
          'day' => '2019-04-02 11:15:00',
          'id' => '275',
          'origin' => 'obseques',
        ),
        1 =>
        array (
          'day' => '2019-04-02 11:15:00',
          'id' => '277',
          'origin' => 'obseques',
        ),
      ),
    ),
  );

在此数组中，我想在名为 ulCreatedDynamic 的关联数组中删除包含 id = 275 和 day = '2019-04-02 11 的键:15:00';

因此必须删除此 key :

0 =>
    array (
      'day' => '2019-04-02 11:15:00',
      'id' => '275',
      'origin' => 'obseques',
    ),

尝试:

$id = 275;
$day = "2019-04-02 11:15:00";

foreach($myArray as $array):
    foreach($array as $ul => $v):
        if($ul == "ulCreatedDynamic"):
            foreach($v as $elementKey => $element):
                if($element['day'] == $day && $element['id'] == $id):
                    unset($v[$elementKey]);
                endif;
            endforeach;
        endif;
    endforeach;
endforeach;

我该如何解决这个问题？

Answer 1

foreach($some_array as $item) 将在任何项目发生更改时立即复制整个数组。您需要使用 & 运算符来处理引用。

foreach($myArray as &$array):
  foreach($array as $ul => &$v):