php - 通过在页面上包含此 PHP 文件，我是在运行其中的所有功能，还是只是允许访问它们？

Question

我有这个函数文件。通过做... <?php include('functions.php'); ?> ...我是在运行其中的所有函数，还是只是允许调用它们(使它们存在于当前范围内)。

抱歉，如果这是一个基本问题，我是一个 PHP 菜鸟!

<?php

  /*
  * -------------------------------------------------------------------------------------
  * ---------------------------- GLOBALLY AVAILABLE FUNCTIONS ---------------------------
  * -------------------------------------------------------------------------------------
  */

  function user_loggedin_check() {
    if(isset($_COOKIE['logged_in']) && ($_COOKIE['logged_in'] == true)){
      $logged_in = true;
      setcookie("logged_in", $logged_in, time()+14400);
      return true;
    } else {
      header('Location: index.php?loginerr=6');
      exit();
    }
  }

  function permission_level_2_check() {
    if(isset($_COOKIE['permission_level']) && ($_COOKIE['permission_level'] == 2)){
      $logged_in = true;
      setcookie("logged_in", $logged_in, time()+14400);
      return true;
    } else {
      setcookie("logged_in", false, time()-1);
      setcookie("permission_level", 1, time()-1);
      session_unset();
      session_destroy();
      header('Location: index.php?loginerr=7');
      exit();
    }
  }

  function permission_level_3_check() {
    if(isset($_COOKIE['permission_level']) && ($_COOKIE['permission_level'] == 3)){
      $logged_in = true;
      setcookie("logged_in", $logged_in, time()+14400);
      return true;
    } else {
      setcookie("logged_in", false, time()-1);
      setcookie("permission_level", 1, time()-1);
      session_unset();
      session_destroy();
      header('Location: index.php?loginerr=7');
      exit();
    }
  }

  function display_login_errors() {
        /*
        * -------------------------------------------------------------------------------------
        * ---------------------------------- ERROR LIST ---------------------------------------
        * -------------------------------------------------------------------------------------
        */
        /*
        * loginerr=0 -> passwords don't match
        * loginerr=1 -> username already exists in DB
        * loginerr=2 -> registration is currently disabled
        * loginerr=3 -> password is too long and/or too short
        * loginerr=4 -> email isn't in proper format
        * loginerr=5 -> email is too long and/or too short
        * loginerr=6 -> user isn't logged in, generic redirect to login page error
        * loginerr=7 -> user doesn't have the required access to view that page
        */

        if(isset($_GET["loginerr"])){
          $loginerr = $_GET["loginerr"];
          switch ($loginerr) {
              case 0:
                  echo "<div class='alert alert-error pagination-centered frontpage-alert'>"; 
                  echo "<strong>Your passwords didn't match. Try again.</strong>";  
                  echo "</div>";
                  break;
              case 1:
                  echo "<div class='alert alert-error pagination-centered frontpage-alert'>"; 
                  echo "<strong>That email address is already registered.</strong>";  
                  echo "</div>";
                  break;
              case 2:
                  echo "<div class='alert alert-error pagination-centered frontpage-alert'>"; 
                  echo "<strong>Registration is currently disabled. Try again later.</strong>";  
                  echo "</div>";
                  break;
              case 3:
                  echo "<div class='alert alert-error pagination-centered frontpage-alert'>"; 
                  echo "<strong>Your password must be between 4 and 32 characters in length.</strong>";  
                  echo "</div>";
                  break;
              case 4:
                  echo "<div class='alert alert-error pagination-centered frontpage-alert'>"; 
                  echo "<strong>Your email address didn't match proper formatting (email@domain.com).</strong>";  
                  echo "</div>";
                  break;
              case 5:
                  echo "<div class='alert alert-error pagination-centered frontpage-alert'>"; 
                  echo "<strong>Your email address must be between 6 and 32 characters in length.</strong>";  
                  echo "</div>";
                  break;
              case 6:
                  echo "<div class='alert alert-error pagination-centered'>"; 
                  echo "<strong>You need to be logged in to access that page. Please log in.</strong>";  
                  echo "</div>";
                  break;
              case 7:
                  echo "<div class='alert alert-error pagination-centered'>"; 
                  echo "<strong>You don't have access to view that page. You have been logged out due to suspicious activity.</strong>";  
                  echo "</div>";
                  break;
          }
        }
      }
 ?>

Answer 1

您只是在定义函数，而不是调用它们。如果该文件中有一个函数调用，它就会执行。通常，您希望将执行代码和函数/类定义分开。

如果您的文件只有函数或类定义，最好使用 include_once(或 require_once)。因为如果您包含该文件两次，您将得到一个函数已存在 错误。使用 include_once 可以避免这种情况。

处理依赖关系的更高级方法是使用 spl_autoload_register 自动加载. Symfony 2 等流行的框架有一个独特的命名方案，允许您将类名映射到文件名，这样任何类都可以及时自动加载。