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php - 在XDK中使用ajax和php删除sql中的数据

转载 作者:搜寻专家 更新时间:2023-10-31 20:36:53 24 4
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我想在 xdk 中按下删除按钮时删除我的 sql 中的一行数据。我搜索了一些代码,但仍然没有删除数据。

这是 php 文件 (delete.php)

<?php
include('dbcon.php');

$foodid = $_POST['foodid'];

$query = "DELETE FROM menu WHERE id ='$foodid'";
$result=mysql_query($query);

if(isset($result)) {
echo "YES";
} else {
echo "NO";
}
?>

现在这是我的 ajax 代码。

$("#btn_delete").click( function(){
alert("1");

var del_id = $(this).attr('foodid');
var $ele = $(this).parent().parent();

alert("2");

$.ajax({
type: 'POST',
url: 'http://localhost/PHP/delete.php',
data: { 'del_id':del_id },
dataType: 'json',
succes: function(data){
alert("3");
if(data=="YES"){
$ele.fadeOut().remove();
} else {
alert("Cant delete row");
}
}
});
});

如您所见,当我在 xdk 中运行程序时,我发出警报以了解我的代码是否正在处理。它只提醒 alert("2"); 。而不是继续 3. 所以我认为我的 ajax 是错误的部分。我对 ajax 有点陌生。

最佳答案

                            <?php
$sqli= "*select * from temp_salesorder *";
$executequery= mysqli_query($db,$sqli);
while($row = mysqli_fetch_array($executequery,MYSQLI_ASSOC))
{
?>

//"class= delbutton" is use to delete data through ajax

<a href="#" **id =<?php echo $row['transaction_id']; ?>** class="**delbutton**" title="Click To Delete"><button> Cancel</button></a>





<!-- language: lang-js -->

//Ajax Code
<script type="text/javascript">
$(function() {


$(".delbutton").click(function(){

//Save the link in a variable called element
var element = $(this);

//Find the id of the link that was clicked
var del_id = element.attr("id");

//Built a url to send
var info = 'id=' + del_id;

$.ajax({
type: "GET",
url: "deletesales.php",
data: info,
success: function(){

}
});
$(this).parents(".record").animate({ backgroundColor: "#fbc7c7" }, "fast")
.animate({ opacity: "hide" }, "slow");



return false;

});

});
</script>

//删除销售.php

<?php
$db_host = 'localhost';
$db_user = 'root';
$db_pass = '';
$db_database = 'pos';
$db = mysqli_connect($db_host,$db_user,$db_pass,$db_database);
$id=$_GET['id']; <!-- This id is get from delete button -->


$result = "DELETE FROM temp_salesorder WHERE transaction_id= '$id'";
mysqli_query($db,$result);

?>



<!-- end snippet -->

关于php - 在XDK中使用ajax和php删除sql中的数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32982261/

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