java - Jooq CustomTypes 生成默认类型 POJO

Question

尝试使用 Joda DateTimes 生成 JooQ POJO，但遇到了一些问题。 POJO 使用默认的 java.sql.TimeStamp 值而不是 DateTimes 从生成器中出来。

下面的代码。

创建表——此处时间戳字段的名称已更改——想要确保我没有在我的构建系统中的某处访问缓存。此名称仍应与以下正则表达式一起使用以进行匹配。

CREATE TABLE nonsense (
  name VARCHAR(50) NOT NULL,
  DATETIME_TEST TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
  id UUID NOT NULL,
  PRIMARY KEY(id)
);

转换类 -- 基于 documentation.

public class LocalDateTimeConverter implements Converter<Timestamp, LocalDateTime> {

    @Override
    public LocalDateTime from(Timestamp databaseObject) {
        return new LocalDateTime(databaseObject.getTime());
    }

    @Override
    public Timestamp to(LocalDateTime dt) {
        return new Timestamp(dt.toDateTime().getMillis());
    }

    @Override
    public Class<Timestamp> fromType() {
        return Timestamp.class;
    }

    @Override
    public Class<LocalDateTime> toType() {
        return LocalDateTime.class;
    }
}

Jooq 配置 XML。基于文档(感谢捕获我的表达式/表达式错误 Luke)!

<configuration>
  <generator>
    <database>
      <customTypes>
        <customType>
          <name>org.joda.time.LocalDateTime</name>
          <converter>n.b.jooqJodaTime.LocalDateTimeConverter</converter>
        </customType>
      </customTypes>
      <forcedtypes>
        <forcedType>
          <name>org.joda.time.LocalDateTime</name>
          <expressions>.*DATETIME.*</expressions>
        </forcedType>
      </forcedtypes>
    </database>
  </generator>
</configuration>

创建的 POJO:

@javax.persistence.Column(name = "DATETIME_TEST", precision = 23, scale = 10)
public java.sql.Timestamp getDatetimeTest() {
    return this.datetimeTest;
}

对于历史背景，这是最初的问题。

---

Create Table:

CREATE TABLE nonsense (
  name VARCHAR(50) NOT NULL,
  TEST_DATETIME TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
  id UUID NOT NULL,
  PRIMARY KEY(id)
);

Converter:

package n.b.jooqJodaTime;

import org.joda.time.DateTime;
import org.jooq.Converter;

import java.sql.Timestamp;

public class DateTimeConverter implements Converter<Timestamp, DateTime> {

    @Override
    public DateTime from(Timestamp databaseObject) {
        return new DateTime(databaseObject.getTime());
    }

    @Override
    public Timestamp to(DateTime dt) {
        return new Timestamp(dt.getMillis());
    }

    @Override
    public Class<Timestamp> fromType() {
        return Timestamp.class;
    }

    @Override
    public Class<DateTime> toType() {
        return DateTime.class;
    }
}

Jooq Configuration:

<configuration>
  <jdbc>
    <url>jdbc:h2:file:build/database</url>
    <driver>org.h2.Driver</driver>
    <user>sa</user>
  </jdbc>
  <generator>
    <database>
      <name>org.jooq.util.h2.H2Database</name>
      <inputSchema>PUBLIC</inputSchema>
      <includes>.*</includes>
      <customTypes>
        <customType>
          <name>org.joda.time.DateTime</name>
          <converter>n.b.jooqJodaTime.DateTimeConverter</converter>
        </customType>
      </customTypes>
      <forcedtypes>
        <forcedType>
          <name>org.joda.time.DateTime</name>
          <expression>.*DATETIME.*</expression>
        </forcedType>
      </forcedtypes>
    </database>
    <generate>
      <pojos>true</pojos>
      <immutablePojos>true</immutablePojos>
      <jpaAnnotations>true</jpaAnnotations>
      <validationAnnotations>true</validationAnnotations>
      <deprecated>false</deprecated>
    </generate>
    <target>
      <packageName>n.b.c.generated.jooq</packageName>
      <directory>src/main/java/</directory>
    </target>
  </generator>
</configuration>

And here are the results:

/**
 * The column <code>PUBLIC.NONSENSE.TEST_DATETIME</code>. 
 */
public final org.jooq.TableField<n.b.c.generated.jooq.tables.records.NonsenseRecord,

java.sql.Timestamp> TEST_DATETIME = createField("TEST_DATETIME", org.jooq.impl.SQLDataType.TIMESTAMP, this);

I'd like this to look like this:

/**
 * The column <code>PUBLIC.NONSENSE.TEST_DATETIME</code>. 
 */
public final org.jooq.TableField<n.b.c.generated.jooq.tables.records.NonsenseRecord,

org.joda.time.DateTime> TEST_DATETIME = createField("TEST_DATETIME", org.jooq.impl.SQLDataType.TIMESTAMP, this);

Answer 1

这可能是因为您的 XML 中有拼写错误。 (出于历史原因)该元素应称为 <expressions/>不是 <expression/> :

  <complexType name="ForcedType">
    <all>
      <!-- The name of the type to be forced upon various artefacts -->
      <element name="name" type="string" minOccurs="1" maxOccurs="1" />

      <!--
        A Java regular expression matching columns, parameters, attributes, 
        etc to be forced to have this type
        -->
      <element name="expressions" type="string" minOccurs="1" maxOccurs="1" />
    </all>
  </complexType>

See also the XSD for details .我认为在 jOOQ 3.3 中为两个元素名称创建同义词是值得的。现在注册为 #2837

另一个错字

<forcedtypes/> 还有一个错字元素，应该是<forcedTypes/> !