java - 使用超时阻塞 ListenableFuture

Question

我正在使用 Spring 4.2.3 AsyncRestTemplate.exchange() 调用一些需要几秒钟的 API，我希望 listenableFuture.get(1, TimeUnit.SECONDS) 将阻塞 1 秒然后抛出超时异常。

取而代之的是 listenableFuture.get() 将在整个 api 调用期间(超过 1 秒)阻塞

    AsyncRestTemplate restTemplate = new AsyncRestTemplate();

    ListenableFuture<ResponseEntity<String>> listenableFuture = restTemplate.exchange(URL, HttpMethod.GET, null, String.class);
    log.debug("before callback");

    //...add callbacks

    try{
        log.debug("before blocking");
        listenableFuture.get(1, TimeUnit.SECONDS);
    }catch (InterruptedException e) {
        log.error(":GOT InterruptedException");
    } catch (ExecutionException e) {
        log.error(":GOT ExecutionException");
    } catch (TimeoutException e) {
        log.info(":GOT TimeoutException");
    }

    log.info("FINISHED");

输出:

    09:15:21.596  DEBUG [main] org.springframework.web.client.AsyncRestTemplate:78 - Created asynchronous GET request for "http://localhost:4567/oia/wait?seconds=5"
    09:15:21.666  DEBUG [main] org.springframework.web.client.RestTemplate:720 - Setting request Accept header to [text/plain, application/xml, text/xml, application/json, application/*+xml, application/*+json, */*]
    09:15:21.679  DEBUG [main] com.zazma.flow.utils.FutureTest:74 - before callback
    09:15:21.679  DEBUG [main] com.zazma.flow.utils.FutureTest:95 - before blocking
    09:15:26.709  DEBUG [main] org.springframework.web.client.AsyncRestTemplate:576 - Async GET request for "http://localhost:4567/oia/wait?seconds=5" resulted in 200 (OK)
    09:15:26.711  DEBUG [main] org.springframework.web.client.RestTemplate:101 - Reading [java.lang.String] as "text/html;charset=utf-8" using [org.springframework.http.converter.StringHttpMessageConverter@3a44431a]
    09:15:26.717   INFO [main] com.zazma.flow.utils.FutureTest:105 - FINISHED

这是一个示例，说明 ListenableFuture.get() 在不是由 AsyncRestTemplate 创建时将按预期工作

SimpleAsyncTaskExecutor te = new SimpleAsyncTaskExecutor();
    ListenableFuture<String> lf = te.submitListenable(() -> {
        Thread.sleep(8000);
        return "OK";
    });

    lf.get(1, TimeUnit.SECONDS);

Answer 1

您的代码完全正确。导致问题的原因是 spring 框架中的错误。虽然，我没有设法在 spring 的问题跟踪器中找到它(或者它可能没有记录)，但您可以通过更新依赖项来修复它。当然，您的代码将适用于 spring-web >= 4.3.2.RELEASE 的版本。