用于选择和比较卡片的 Java 代码(没有 Arraylist)

Question

我看到很多与此类似的问题，但它们的答案是我还没有学过的代码。我应该能够在没有数组列表的情况下完成这项任务，这对我来说是一个挑战。我需要玩一场 war 游戏:创建一个卡片类别，创建一个牌组然后随机生成第一张牌，从牌组中“移除”该牌并制作第二张牌以查看哪张牌获胜，继续比较直到甲板已经用完了。这是我目前所拥有的:

public class Card
{
private int cardValue; 
private String cardSuit;
private String stringValue;
static final String[] SUIT = {"Clubs", "Diamonds", "Hearts", "Spades"}; 
static final String[] VALUE =  {"Ace","Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Jack", "Queen", "King"}; 


/**
*CONSTRUCTOR for Card class
*contains the arrays for both suit and values
**/
public Card (int cardS, int cardV)
{

    cardSuit = SUIT[cardS]; 
    stringValue = VALUE[cardV];
}

/**
*Get method for card suit, access the value of cardSuit
**/
public String getCardSuit()
{
        return cardSuit;
}

/**
*get method for card's VALUES
**/
public String getValue()
{
    return stringValue;
}
//in order to display string value of cards
public String toString() 
{ 
    return String.format("%s of %s", stringValue, cardSuit); 
} 

public class Deck
    {
    private final int HIGH_SUIT=3;
    private final int HIGH_VALUE=12;

    int i = 0; 
    int cardCount;              

    Card[] fullDeck = new Card[52]; 
    public Deck()
    {

        for(int s = 0; s <= HIGH_SUIT; s++)
        {
            //for loop to determine the suit
            for (int v = 0; v <= HIGH_VALUE; v++)
            {
                //construct all 52 cards and print them out 
                fullDeck[i] = new Card(s, v);
                cardCount = (i + 1);
                i++;//increment the card counter

            }
        }   
    }

public class War3

{
public static void main(String[] args)
{
    int i=0;
    Deck[] fullDeck = new Deck[52]; //set up the deck
    //create a random value for the first card
    int r = ((int) (Math.random() * 100) % 51);//create random number

    Card[] playerCard = new Card[r];//create the player's card

    System.out.println("The card is: " + playerCard.toString());


    }

如您所见，我对 War 3 并没有深入了解，因为我不知道如何展示第一张牌。运行时显示:The card is: [LCard;@4a5ab2random#1如何显示数组中的第一张卡片？我需要帮助弄清楚如何分配第一张卡片和第二张卡片，同时显示它们然后比较它们。我还有很长的路要走，所以一步一个脚印。

Answer 1

最简单的做法是在您的 Card 类中实现一个 toString 方法。

public String toString() {
    return String.format("%s of %s", stringValue, cardSuit);
}

当你这样做时，将两个数组(suit 和 value)移出构造函数，使它们成为 static final，然后重命名为全大写:

static final String[] SUIT = {"Clubs", "Diamonds", "Hearts", "Spades"};
static final String[] VALUE = {"Ace","Two", "Three", "Four", "Five", "Six", "Seven",
                "Eight", "Nine", "Ten", "Jack", "Queen", "King"};

此外，卡片的选择不应该像您那样完成:

Card[] playerCard = new Card[r];//create the player's card

创建一个 r 卡片数组，并将其分配给 playerCard。这是不正确的:您已经在 Deck 中创建了所有卡片，只需从中随机抽取一张即可:

public Card takeRandomCard() {
    int r;
    do {
        r = (int)(Math.random() * 52);
    } while (taken[r]);
    taken[r] = true;
    return fullDeck[r];
}

注意这里的小补充:taken 是一个包含 52 个 boolean 对象的数组，表示该牌已从牌组中拿走。

这是您的 code with my modifications从上面在 ideone 工作。