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java - Maven WADL 插件没有生成可用的 WADL

转载 作者:搜寻专家 更新时间:2023-10-31 20:09:19 25 4
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我正在尝试使用 maven 插件生成 WADL。项目构建和服务工作。这是带有插件的 POM 部分:

             <plugin>
<groupId>com.sun.jersey.contribs</groupId>
<artifactId>maven-wadl-plugin</artifactId>
<version>1.19.2</version>
<executions>
<execution>
<id>generate</id>
<goals>
<goal>generate</goal>
</goals>
<phase>package</phase>
</execution>
</executions>

<configuration>
<wadlFile>${basedir}/src/main/docs/ThingREST.wadl</wadlFile>
<formatWadlFile>true</formatWadlFile>
<baseUri>http://localhost:8080/ThingREST</baseUri>
<packagesResourceConfig>
<param>samp.rest.ws.controller</param>
</packagesResourceConfig>
<wadlGenerators>
<wadlGeneratorDescription>
<className>com.sun.jersey.server.wadl.generators.WadlGeneratorApplicationDoc
</className>
<properties>
<property>
<name>applicationDocsFile</name>
<value>${basedir}/src/main/docs/xml/app-wadl-doc.xml</value>
</property>
</properties>
</wadlGeneratorDescription>
<wadlGeneratorDescription>
<className>com.sun.jersey.server.wadl.generators.WadlGeneratorGrammarsSupport
</className>
<properties>
<property>
<name>grammarsFile</name>
<value>${basedir}/src/main/docs/xml/app-wadl-grammar.xml</value>
</property>
</properties>
</wadlGeneratorDescription>
</wadlGenerators>
</configuration>
</plugin>

applicationDocFile 和 grammarFile 存在,但它们不包含任何重要信息。我不确定要包括什么。

这是 Controller :

package samp.rest.ws.controller;

import java.util.List;
import samp.rest.ws.ThingDB;
import samp.rest.ws.vo.Thing;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RestController;

/**
*
* @author Grayson
*/
@RestController
public class ThingController {

@RequestMapping(value = "/things", method = RequestMethod.GET, headers = "Accept=application/json") //produces = "application/json")
public List<Thing> getThings() {
return ThingDB.getThings();
}

@RequestMapping(value = "/thing/{id}", method = RequestMethod.GET, headers = "Accept=application/json")
public Thing getThingById(@PathVariable int id) {
return ThingDB.getThing(id);
}

@RequestMapping(value = "/thingy/{id}", method = RequestMethod.GET)
public String getThingy(@PathVariable int id) {
return ThingDB.getThing(id).toString();
}

@RequestMapping(value = "/addthing", method = RequestMethod.PUT) //, headers = "Accept=application/json")
public void addThing(@RequestBody Thing thing) {
ThingDB.addThing(thing);

List<Thing> lt = ThingDB.getThings();
for (Thing t : lt) {
System.out.println(" Post add: " + t.toString());
}
}
}

最后,这是生成的 WADL:

<?xml version="1.0" encoding="UTF-8"?>
<application xmlns="http://wadl.dev.java.net/2009/02">
<doc
jersey:generatedBy="Jersey: 1.19.2 08/25/2016 12:00 AM"
xmlns:jersey="http://jersey.java.net/"/>
<doc
title="Maven Spring REST Sample WADL"
xml:lang="en"><![CDATA[
This is the Web Application Description Language (WADL) for
a Maven Spring REST Service. This service is intended to serve as
a workign model/sample.
]]></doc>
<grammars/>
<resources base="http://localhost:8080/ThingREST"/>
</application>

我期望 WADL 包含可用的服务调用并识别输入类型。显然,我不明白这一点。

我到处搜索示例和文档以使用此插件。任何和所有帮助将不胜感激。遗憾的是,现有的文档/示例似乎已经过时了。

提前致谢。

最佳答案

不幸的是,这个插件不支持 Spring REST Controller 。它只会处理用 @Path 和其他 JAX-RS 注释注释的类。没有其他插件可以满足您的需求。您有两个选择:

1) 重写您的 Controller 以使用 JAX-RS。例如,我将您的 Controller 更改为以下内容:

package samp.rest.ws.controller;

import java.util.List;
import samp.rest.ws.ThingDB;
import samp.rest.ws.vo.Thing;

import javax.ws.rs.*;

@Path("/thing")
public class ThingController {

@GET
@Path(value = "/things")
@Produces("application/json")
public List<Thing> getThings() {
return ThingDB.getThings();
}

@GET
@Path(value = "/thing/{id}")
@Produces("application/json")
public Thing getThingById(@PathParam("id") int id) {
return ThingDB.getThing(id);
}

@GET
@Path(value = "/thingy/{id}")
public String getThingy(@PathParam("id") int id) {
return ThingDB.getThing(id).toString();
}

@PUT
@Path(value = "/addthing")
@Produces("application/json")
public void addThing(Thing thing) {
ThingDB.addThing(thing);

List<Thing> lt = ThingDB.getThings();
for (Thing t : lt) {
System.out.println(" Post add: " + t.toString());
}
}
}

然后插件生成这个 WADL 文件:

<?xml version="1.0" encoding="UTF-8"?>
<application xmlns="http://wadl.dev.java.net/2009/02">
<doc jersey:generatedBy="Jersey: 1.19.2 08/25/2016 12:00 AM" xmlns:jersey="http://jersey.java.net/"/>
<doc title="A message in the WADL" xml:lang="en"><![CDATA[This is the Web Application Description Language (WADL) for
a Maven Spring REST Service. This service is intended to serve as
a workign model/sample.]]></doc>
<grammars>
<include href="xsd0.xsd">
<doc/>
</include>
</grammars>
<resources base="http://localhost:8080/ThingREST">
<resource path="/thing">
<resource path="/things">
<method id="getThings" name="GET">
<response>
<representation mediaType="application/json"/>
</response>
</method>
</resource>
<resource path="/addthing">
<method id="addThing" name="PUT">
<request>
<representation mediaType="*/*"/>
</request>
</method>
</resource>
<resource path="/thing/{id}">
<param name="id" style="template" type="xs:int" xmlns:xs="http://www.w3.org/2001/XMLSchema"/>
<method id="getThingById" name="GET">
<response>
<representation mediaType="application/json"/>
</response>
</method>
</resource>
<resource path="/thingy/{id}">
<param name="id" style="template" type="xs:int" xmlns:xs="http://www.w3.org/2001/XMLSchema"/>
<method id="getThingy" name="GET">
<response>
<representation mediaType="*/*"/>
</response>
</method>
</resource>
</resource>
</resources>
</application>

2) 编写您自己的支持 Spring REST Controller 的 Maven WADL 插件。作为引用,您可以以网络服务的形式查看此生成器:

https://javattitude.com/2014/05/26/wadl-generator-for-spring-rest/

以及Maven WADL插件的源码:

https://github.com/jersey/jersey-1.x/tree/master/contribs/maven-wadl-plugin

关于java - Maven WADL 插件没有生成可用的 WADL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39859814/

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