java - 错误 : incompatible types: possible lossy conversion from int to short. 我不知道为什么会收到此错误消息

Question

public class Demo 
{
    public static void main(String[] args) 
    {
       int a=10,b=20;
       short c = (a<b)?a:b;
       System.out.println(c);
    }
}

这是我的程序，我遇到以下错误，为什么我没有得到

"Demo.java:6: error: incompatible types: possible lossy conversion from int to short
short c = (a<b)?a:b;
1 error" 

我写了带有变量声明的“final”，它工作正常。但为什么会这样呢？

public class Demo 
{
    public static void main(String[] args) 
    {
        final int a=10,b=20;
        short c = (a<b)?a:b;
        System.out.println(c);
    }
}

Answer 1

要回答您的问题，您基本上是向下转换 int 数据类型为short Java 中 Not Acceptable 情况。为了详细描述，下面是详细描述:-

案例 1:-

public class Demo 
{
    public static void main(String[] args) 
    {
       int a=10,b=20;
       short c = (a<b)?a:b;
       System.out.println(c);
    }
}

在这种情况下，您只是将数据类型从int向下转换 为short，这是抛出

error: incompatible types: possible lossy conversion from int to short

案例 2:-

public class Demo 
{
    public static void main(String[] args) 
    {
        final int a=10,b=20;
        short c = (a<b)?a:b;
        System.out.println(c);
    }
}

In this scenario, since you have declared your variables viz. a & b as final. As a result, both the values becomes CONSTANT for variable c. It means for the variable c, the values of a & b won't get changed & it has been finalized to 20 which is in range of short data type (-32,768 to 32,767). Therefore, you won't get any error unless & until you keep the value within the range.

真实测试用例:-

public class Demo 
{
    public static void main(String[] args) 
    {
        final int a=32768,b=32788;
        short c = (a<b)?a:b;
        System.out.println(c);
    }
}

编译这个类，看看它的神奇之处!您将再次遇到相同的错误。

For your further understanding, please refer here to get a clear picture in general.

这个故事的寓意:- 只是不要贬低你的数据类型!!