java - 什么是 Java 等同于使用 https ://fcm. googleapis.com/fcm/send REST Api

Question

我已经尝试在 Curl 中使用以下命令使用 Firebase REST Api 发送通知并且它有效:

curl -X POST --header "Authorization: key=AIza...iD9wk" --Header "Content-Type: application/json" https://fcm.googleapis.com/fcm/send -d "{\"notification\":{\"title\": \"My title\", \"text\": \"My text\", \"sound\": \"default\"}, \"to\": \"cAhmJfN...bNau9z\"}"

现在我正尝试在 Java 中做同样的事情，但我找不到一种简单的方法来做同样的事情，而且我尝试过的任何方法都不会触发我的移动端点中的通知。

这是我最接近的方法:

    try {
        HttpURLConnection httpcon = (HttpURLConnection) ((new URL("https://fcm.googleapis.com/fcm/send").openConnection()));
        httpcon.setDoOutput(true);
        httpcon.setRequestProperty("Content-Type", "application/json");
        httpcon.setRequestProperty("Authorization: key", "AIza...iD9wk");
        httpcon.setRequestMethod("POST");
        httpcon.connect();
        System.out.println("Connected!");

        byte[] outputBytes = "{\"notification\":{\"title\": \"My title\", \"text\": \"My text\", \"sound\": \"default\"}, \"to\": \"cAhmJfN...bNau9z\"}".getBytes("UTF-8");
        OutputStream os = httpcon.getOutputStream();
        os.write(outputBytes);
        os.close();

        // Reading response
        InputStream input = httpcon.getInputStream();
        try (BufferedReader reader = new BufferedReader(new InputStreamReader(input))) {
            for (String line; (line = reader.readLine()) != null;) {
                System.out.println(line);
            }
        }

        System.out.println("Http POST request sent!");
    } catch (IOException e) {
        e.printStackTrace();
    }

但后来我得到:

java.io.IOException: Server returned HTTP response code: 401 for URL: https://fcm.googleapis.com/fcm/send
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1625)
    at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java:254)
    at httpclient.test.MyHttpClientPost.sendNotification(MyHttpClientPost.java:131)
    at httpclient.test.MyHttpClientPost.main(MyHttpClientPost.java:26)

Answer 1

401 表示未经授权，因此未发送有效的 Authorization header 。

还有这一行:

httpcon.setRequestProperty("Authorization: key", "AIza...iD9wk");

不等同于 -H "Authorization: key=AIza...iD9wk"。第一个参数应该是 header 名称，即 Authorization:

httpcon.setRequestProperty("Authorization", "key=AIza...iD9wk");

总之，您误解了 HTTP header 的格式。基本上， header 名称和值由 : 而不是 = 分隔。