java - 使用 Mockito 时避免未经检查的警告

Question

我想在 ScheduledExecutorService 上模拟一个电话返回 ScheduledFuture 的模拟类时方法 schedule被调用。以下代码编译并正常工作:

    ScheduledExecutorService executor = Mockito.mock(ScheduledExecutorService.class);
    ScheduledFuture future = Mockito.mock(ScheduledFuture.class);
    Mockito.when(executor.schedule(
        Mockito.any(Runnable.class),
        Mockito.anyLong(),
        Mockito.any(TimeUnit.class))
    ).thenReturn(future); // <-- warning here

除了我在最后一行收到未经检查的警告:

found raw type: java.util.concurrent.ScheduledFuture
  missing type arguments for generic class java.util.concurrent.ScheduledFuture<V>

 unchecked method invocation: method thenReturn in interface org.mockito.stubbing.OngoingStubbing is applied to given types
  required: T
  found: java.util.concurrent.ScheduledFuture

unchecked conversion
  required: T
  found:    java.util.concurrent.ScheduledFuture

是否有可能以某种方式避免这些警告？

代码类似于 ScheduledFuture<?> future = Mockito.mock(ScheduledFuture.class);不编译。

Answer 1

当使用模拟规范的替代方式时，所有警告都会消失:

    ScheduledFuture<?> future = Mockito.mock(ScheduledFuture.class);
    Mockito.doReturn(future).when(executor).schedule(
        Mockito.any(Runnable.class),
        Mockito.anyLong(),
        Mockito.any(TimeUnit.class)
    );