ios - 在 Alamofire 中快速发送 GET 请求中的 json 对象

Question

我正在尝试执行一个绑定(bind)了 json 对象的 GET 请求，这就是我生成 JSON 对象的方式

   let jsonObject: [String: AnyObject] = [

        "ean_code": [
            "type": "match",
            "value": "16743799"
        ]
    ]

然后我执行了请求

像这样

        Alamofire.request(.GET,Constant.WebClient.WS_URL + "/product?filters="+String(jsonObject),parameters:parameters)

但这给了我一个错误，它不能用无效字符绑定(bind) URL

所以我对这个 URL 进行了编码

let request = String(jsonObject).stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPasswordAllowedCharacterSet())!

这将对 URL 进行编码，但我又会出现以下错误

Request failed with error: Error Domain=NSCocoaErrorDomain Code=3840 "Invalid value around character 0." UserInfo={NSDebugDescription=Invalid value around character 0.}

所以我的问题是如何将 json 对象绑定(bind)到 GET URL？

Answer 1

做这样的事情

let parameters: [String: AnyObject] = [

    "filters": "merchantName",
    "ean_code": [
        "type": "match",
        "value": "16743799"
    ]
]

do {
    let data = try NSJSONSerialization.dataWithJSONObject(parameters, options: .PrettyPrinted)
    let jsonString = NSString(data: data, encoding: NSUTF8StringEncoding)
    let urlEncodedJson = jsonString!.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())
    let urlString = "http://www.filter.com/&params=\(urlEncodedJson!)"
    let url = NSURL(string: urlString)
    // Trigger alaomofire request with url
}
catch let JSONError as NSError {
    print("\(JSONError)")
}