java - antlr4/java : pretty print parse tree to stdout

Question

初学者问题:如何将解析树的可读版本打印到标准输出？

CharStream input = CharStreams.fromFileName("testdata/test.txt");
MyLexer lexer = new MyLexer(input);
CommonTokenStream tokens = new CommonTokenStream(lexer);
MyParser parser = new MyParser(tokens);     
parser.setBuildParseTree(true);
RuleContext tree = parser.record();
System.out.println(tree.toStringTree(parser));

这会将整个树打印在由方括号“()”分隔的一行中。

(record (husband <4601>   (name KOHAI   Nikolaus) \n (birth *   um.1872   (place Ploschitz)) \n\n) (wife      (marriage oo) \n      (name SCHLOTTHAUER   Maria) \n      (birth *   um.1877  
...

我想要这样的东西

record 
  husband
    <id>
    name
       <name>
...
  wife

Answer 1

摘自SnippetsTest作为一个独立的实用程序类:

import java.util.List;

import org.antlr.v4.runtime.misc.Utils;
import org.antlr.v4.runtime.tree.Tree;
import org.antlr.v4.runtime.tree.Trees;

public class TreeUtils {

    /** Platform dependent end-of-line marker */
    public static final String Eol = System.lineSeparator();
    /** The literal indent char(s) used for pretty-printing */
    public static final String Indents = "  ";
    private static int level;

    private TreeUtils() {}

    /**
     * Pretty print out a whole tree. {@link #getNodeText} is used on the node payloads to get the text
     * for the nodes. (Derived from Trees.toStringTree(....))
     */
    public static String toPrettyTree(final Tree t, final List<String> ruleNames) {
        level = 0;
        return process(t, ruleNames).replaceAll("(?m)^\\s+$", "").replaceAll("\\r?\\n\\r?\\n", Eol);
    }

    private static String process(final Tree t, final List<String> ruleNames) {
        if (t.getChildCount() == 0) return Utils.escapeWhitespace(Trees.getNodeText(t, ruleNames), false);
        StringBuilder sb = new StringBuilder();
        sb.append(lead(level));
        level++;
        String s = Utils.escapeWhitespace(Trees.getNodeText(t, ruleNames), false);
        sb.append(s + ' ');
        for (int i = 0; i < t.getChildCount(); i++) {
            sb.append(process(t.getChild(i), ruleNames));
        }
        level--;
        sb.append(lead(level));
        return sb.toString();
    }

    private static String lead(int level) {
        StringBuilder sb = new StringBuilder();
        if (level > 0) {
            sb.append(Eol);
            for (int cnt = 0; cnt < level; cnt++) {
                sb.append(Indents);
            }
        }
        return sb.toString();
    }
}

调用方法如下:

List<String> ruleNamesList = Arrays.asList(parser.getRuleNames());
String prettyTree = TreeUtils.toPrettyTree(tree, ruleNamesList);