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iOS YouTube 分享扩展不提供 URL

转载 作者:搜寻专家 更新时间:2023-10-31 19:28:36 25 4
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我的共享扩展中有以下代码来获取共享的 URL。

    if let item = extensionContext?.inputItems.first as? NSExtensionItem {
for (index, _) in (item.attachments?.enumerated())! {
if let itemProvider = item.attachments?[index] as? NSItemProvider {
if itemProvider.hasItemConformingToTypeIdentifier("public.url") {
itemProvider.loadItem(forTypeIdentifier: "public.url", options: nil, completionHandler: { (url, error) -> Void in
if let shareURL = url as? NSURL {
// send url to server to share the link
print (shareURL.absoluteString!)

出于某种原因,iOS YouTube 应用程序为 itemProvider.hasItemConformingToTypeIdentifier("public.url") 返回 false。

下面是我的共享扩展的 Info.plist。

<key>NSExtension</key>
<dict>
<key>NSExtensionAttributes</key>
<dict>
<key>NSExtensionActivationRule</key>
<string>
SUBQUERY (
extensionItems,
$extensionItem,
SUBQUERY (
$extensionItem.attachments,
$attachment,
ANY $attachment.registeredTypeIdentifiers UTI-CONFORMS-TO "public.url"
).@count == 1
).@count == 1
</string>
</dict>
<key>NSExtensionMainStoryboard</key>
<string>MainInterface</string>
<key>NSExtensionPointIdentifier</key>
<string>com.apple.share-services</string>
</dict>

如何获取在我的分享扩展中分享的 YouTube 视频的 URL?

最佳答案

我的第一个建议是找出itemProvider:

if let item = extensionContext?.inputItems.first as? NSExtensionItem {
for (index, _) in (item.attachments?.enumerated())! {
if let itemProvider = item.attachments?[index] as? NSItemProvider {

// print out the registered type identifiers so we can see what's there
itemProvider.registeredTypeIdentifiers.forEach { print String(describing: $0) }

在这种情况下,根据您的评论,您可以获得纯文本或 kUTTypePlainText 并且该文本包含一个 URL,因此:

if let item = extensionContext?.inputItems.first as? NSExtensionItem {
for (index, _) in (item.attachments?.enumerated())! {
if let itemProvider = item.attachments?[index] as? NSItemProvider {
if itemProvider.hasItemConformingToTypeIdentifier(kUTTypePlainText) {
itemProvider.loadItem(forTypeIdentifier: kUTTypePlainText, options: nil, completionHandler: { (string, error) -> Void in
if let string = (string as? String), let shareURL = URL(string) {
// send url to server to share the link
print (shareURL.absoluteString!)

我的第二个建议是始终使用 kUTType 常量而不是原始字符串:-)

关于iOS YouTube 分享扩展不提供 URL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43954725/

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