swift - 测试实例是否是 Swift 中带有类型别名的协议(protocol)？

Question

这与 this question 有关.使用 typealias 我可以创建一个具有“子”var 但具有特定类型的类，这正是我正在寻找的。但是当我这样做时，我无法再测试一个实例是否遵循该协议(protocol)。我也尝试过“if let”，但没有用。有什么办法吗？

protocol Parent {
    typealias Child
    var children: [Child] { get set }
}

protocol Child {
    typealias Parent
    var parent: Parent { get set }

}

class Foo: Parent {
    var children = [Bar]()

    init(){}
}

class Bar: Child {
    var parent = Foo()
}

let testVar = Foo()
let cVar = Bar()

testVar.children.append(cVar)
cVar.parent = testVar

//I get the error here saying protocol is limited to generic constraints
if testVar is Parent { 

}

Answer 1

不幸的是，没有办法静态地解决这个问题(至少目前是这样)。因此，一种更动态的方法是拥有一个没有自关联类型要求的“ super ”协议(protocol)。这允许您在这些“ super ”协议(protocol)之间进行转换:

protocol _Parent {
    var anyChildren: [Any] { get set }
}
protocol Parent: _Parent {
    typealias Child
    var children: [Child] { get set }
}

extension Parent {
    // requirement of _Parent
    var anyChildren: [Any] {
        get {
            return children.map{ $0 as Any }
        }
        set {
            // use `as!` and `map` if you are sure that all elements are of type Child
            // or if you want a crash if not
            children = newValue.flatMap{ $0 as? Child }
        }
    }
}

protocol _Child {
    var anyParent: Any { get set }
}

protocol Child: _Child {
    typealias Parent
    var parent: Parent { get set }
}

extension Child {
    // requirement of _Child
    var anyParent: Any {
        get {
            return parent
        }
        set {
            parent = newValue as! Parent
        }
    }
}

现在您可以使用它们的属性来操作数据:

class Foo: Parent {
    var children = [Foo]()
}

let anything: Any = Foo()

// use `if let` and `as?` instead of `is` in order to have a more static type
if let aDynamicParent = anything as? _Parent {
    aDynamicParent.anyChildren.map{ $0 as! Foo } // cast the array back to its original type

    aDynamicParent.children = [Foo(), Foo(), Foo()]
}