ios - 关闭并弹出一个 View Controller

Question

我想在我的 View Controller 堆栈上返回两个级别。我按此顺序有三个 segue:Show、Show、Present Modally。有一个导航 Controller 正在使用中。从我的第 4 个 View 我想回到第 2 个 View 。我试过使用 self.presentingViewController?.presentingViewController?.navigationController?.popViewControllerAnimated(false);

和

self.presentingViewController?.presentingViewController?.dismissViewControllerAnimated(false, completion: nil);

第二个仅在第二个和第三个 segues 为“Present Modally”时才有效。我怎样才能让他们在解雇和流行的情况下工作？

Answer 1

尝试在弹出其他两个之前关闭呈现的 View Controller :

func dismissThenDoublePop() {

    // Get the presenting/previous view
    let previousView = self.presentingViewController as UINavigationController

    // Dismiss the current view controller then pop the others
    // upon completion
    self.dismissViewControllerAnimated(true, completion:  {

        // Get an array of the current view controllers on your nav stack
        let viewControllers: [UIViewController] = previousView.viewControllers as [UIViewController];

        // Then either pop two view controllers, i.e. pop
        // to viewControllers[viewControllers.count - 2], or
        // pop to the second view controller in the nav stack,
        // i.e. viewControllers[1]. (In this case I've used the
        // first option.)
        self.navigationController!.popToViewController(viewControllers[viewControllers.count - 2], animated: true);

    });
}