ios - 使用 UIDatePicker 而不是键盘来处理 UITextField 问题

Question

您好，我正在尝试在点击 UITextField 时显示 UIDatePicker 而不是键盘，以便用户可以为事件指定开始和结束时间。我的代码有效但效果不佳，而且不是我想要的方式。

我的第一个问题是，每当您点击其中一个 UITextField 时，UIDatePicker 只会在第二次点击 UITextField 时出现。否则它会显示原始键盘。

我的第二个问题是，无论何时编辑 UIDatePicker，只要编辑 UIDatePicker，它只会更改 UITextField。我需要 UITextField 在 UIDatePicker 打开后立即显示字符串，以便 UITextField 与正在发生的事情保持同步UIDatePicker。

这是我当前的代码:

override func viewDidLoad() {
super.viewDidLoad()
 var datePickerView  : UIDatePicker = UIDatePicker()
    datePickerView.datePickerMode = UIDatePickerMode.Time
    StartTimeTextField.inputView = datePickerView
    datePickerView.addTarget(self, action:
    Selector("handleDatePicker:"), forControlEvents: UIControlEvents.ValueChanged)

    var datePickerView2  : UIDatePicker = UIDatePicker()
    datePickerView2.datePickerMode = UIDatePickerMode.Time
    EndTimeTextField.inputView = datePickerView2
    datePickerView2.addTarget(self, action: Selector("handleDatePicker2:"), forControlEvents: UIControlEvents.ValueChanged)
    }

func handleDatePicker(sender: UIDatePicker) {
    var dateFormatter = NSDateFormatter()
    dateFormatter.dateFormat = "hh mm am pm"
    StartTimeTextField.text = dateFormatter.stringFromDate(sender.date)
}



func handleDatePicker2(sender: UIDatePicker) {
    var dateFormatter = NSDateFormatter()
    dateFormatter.dateFormat = "hh mm am pm"
    EndTimeTextField.text = dateFormatter.stringFromDate(sender.date)
}

谁能帮帮我？谢谢

Answer 1

为什么你要通过 Action 来改变键盘!

只需在 viewDidLoad 中添加您的代码:

var datePickerView  : UIDatePicker = UIDatePicker()
datePickerView.datePickerMode = UIDatePickerMode.Time
StartTimeTextField.inputView = datePickerView
datePickerView.addTarget(self, action: Selector("handleDatePicker:"), forControlEvents: UIControlEvents.ValueChanged)

var datePickerView  : UIDatePicker = UIDatePicker()
datePickerView.datePickerMode = UIDatePickerMode.Time
EndTimeTextField.inputView = datePickerView
datePickerView.addTarget(self, action: Selector("handleDatePicker2:"), forControlEvents: UIControlEvents.ValueChanged)

并删除像

这样的方法

@IBAction func