ios - 在 performSegueWithIdentifier 之后不调用 prepareForSegue

Question

我是 iOS 开发新手。有很多重复的问题(抱歉)。但是我无法解决这个问题。

调用 performSegueWithIdentifier 后不会调用 prepareForSegue。

show segue 标识符被命名为“segue1”。Ctrl-从 ViewController 拖动到 DetailViewController。

我错过了什么吗？

ViewController.swift:

class ViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
}

@IBAction func buttonTapped(sender: AnyObject) {
    print("ViewController - buttonTapped()")
    performSegueWithIdentifier("segue1", sender: self)
}

override func performSegueWithIdentifier(identifier: String, sender: AnyObject?) {
    print("ViewController - performSegueWithIdentifier(): \(identifier)")
}

override func shouldPerformSegueWithIdentifier(identifier: String, sender: AnyObject?) -> Bool {
    print("ViewController - shouldPerformSegueWithIdentifier()")
    return true
}

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    print("ViewController - prepareForSegue(): \(segue.identifier!)")
}
}

DetailViewController.swift:

class DetailViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()

    print("DetailViewController - viewDidLoad()")
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
}
}

这是一个screenshot of storyboard .

输出(点击按钮后)

ViewController - buttonTapped()
ViewController - performSegueWithIdentifier(): segue1

Answer 1

您没有调用 super - 添加以下内容以将消息发送到父类(这将依次触发 segue)

super.performSegueWithIdentifier(identifier, sender: sender)