swift - 使用 UITapGestureRecognizer、UIImageView 和 UITableViewCell 将参数传递给 Swift 中的选择器

Question

我需要识别用户在 TableCell 上单击的 image。

如何传递TAG？

class CustomCell: UITableViewCell {
@IBOutlet weak var imgPost1: UIImageView!

override func awakeFromNib() {
    super.awakeFromNib()
    // Initialization code
    imgPost1.tag=1
    let tap = UITapGestureRecognizer(target: self, action: #selector(CustomCell.tappedMe))
    imgPost1.addGestureRecognizer(tap)
    imgPost1.userInteractionEnabled = true
}
func tappedMe(xTag:Int) {
    print(xTag)
}

override func setSelected(selected: Bool, animated: Bool) {
    super.setSelected(selected, animated: animated)

    // Configure the view for the selected state
}
}

Answer 1

您可以使用 UIGestureRecognizer 的 view 属性。

注册点击手势:

let tap = UITapGestureRecognizer(target: self, action: "tappedMe:")
imgPost1.addGestureRecognizer(tap)
imgPost1.userInteractionEnabled = true

现在定义 tappedMe 方法

func tappedMe(sender: UITapGestureRecognizer) {
    print(sender.view?.tag)
}

PS:不要忘记给图片设置标签