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ios - 让 CIColorCube 过滤器在 Swift 中工作

转载 作者:搜寻专家 更新时间:2023-10-31 08:21:26 26 4
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我正在尝试让 CIColorCube 过滤器正常工作。然而,Apple 文档仅在此处提供了一个解释不清的引用示例:

// Allocate memory
const unsigned int size = 64;
float *cubeData = (float *)malloc (size * size * size * sizeof (float) * 4);
float rgb[3], hsv[3], *c = cubeData;

// Populate cube with a simple gradient going from 0 to 1
for (int z = 0; z < size; z++){
rgb[2] = ((double)z)/(size-1); // Blue value
for (int y = 0; y < size; y++){
rgb[1] = ((double)y)/(size-1); // Green value
for (int x = 0; x < size; x ++){
rgb[0] = ((double)x)/(size-1); // Red value
// Convert RGB to HSV
// You can find publicly available rgbToHSV functions on the Internet
rgbToHSV(rgb, hsv);
// Use the hue value to determine which to make transparent
// The minimum and maximum hue angle depends on
// the color you want to remove
float alpha = (hsv[0] > minHueAngle && hsv[0] < maxHueAngle) ? 0.0f: 1.0f;
// Calculate premultiplied alpha values for the cube
c[0] = rgb[0] * alpha;
c[1] = rgb[1] * alpha;
c[2] = rgb[2] * alpha;
c[3] = alpha;
c += 4; // advance our pointer into memory for the next color value
}
}
}
// Create memory with the cube data
NSData *data = [NSData dataWithBytesNoCopy:cubeData
length:cubeDataSize
freeWhenDone:YES];
CIColorCube *colorCube = [CIFilter filterWithName:@"CIColorCube"];
[colorCube setValue:@(size) forKey:@"inputCubeDimension"];
// Set data for cube
[colorCube setValue:data forKey:@"inputCubeData"];

所以我尝试使用以下内容将其转换为 Swift:

var filter = CIFilter(name: "CIColorCube")
filter.setValue(ciImage, forKey: kCIInputImageKey)
filter.setDefaults()

var size: UInt = 64
var floatSize = UInt(sizeof(Float))
var cubeDataSize:size_t = size * size * size * floatSize * 4
var colorCubeData:Array<Float> = [
0,0,0,1,
0,0,0,1,
0,0,0,1,
0,0,0,1,
0,0,0,1,
0,0,0,1,
0,0,0,1,
0,0,0,1
]

var cubeData:NSData = NSData(bytesNoCopy: colorCubeData, length: cubeDataSize)

但是在尝试创建多维数据集数据时出现错误:

"Extra argument 'bytesNoCopy' in call"

基本上我创建的 cubeData 是错误的。你能告诉我如何在 Swift 中正确创建 cubeData 对象吗?

谢谢!

最佳答案

看起来您正在寻找色度键滤镜配方 described here .这是一些有效的代码。你会得到一个你想要透明的颜色的过滤器,用它的 HSV 角度描述:

func RGBtoHSV(r : Float, g : Float, b : Float) -> (h : Float, s : Float, v : Float) {
var h : CGFloat = 0
var s : CGFloat = 0
var v : CGFloat = 0
let col = UIColor(red: CGFloat(r), green: CGFloat(g), blue: CGFloat(b), alpha: 1.0)
col.getHue(&h, saturation: &s, brightness: &v, alpha: nil)
return (Float(h), Float(s), Float(v))
}

func colorCubeFilterForChromaKey(hueAngle: Float) -> CIFilter {

let hueRange: Float = 60 // degrees size pie shape that we want to replace
let minHueAngle: Float = (hueAngle - hueRange/2.0) / 360
let maxHueAngle: Float = (hueAngle + hueRange/2.0) / 360

let size = 64
var cubeData = [Float](repeating: 0, count: size * size * size * 4)
var rgb: [Float] = [0, 0, 0]
var hsv: (h : Float, s : Float, v : Float)
var offset = 0

for z in 0 ..< size {
rgb[2] = Float(z) / Float(size) // blue value
for y in 0 ..< size {
rgb[1] = Float(y) / Float(size) // green value
for x in 0 ..< size {

rgb[0] = Float(x) / Float(size) // red value
hsv = RGBtoHSV(r: rgb[0], g: rgb[1], b: rgb[2])
// the condition checking hsv.s may need to be removed for your use-case
let alpha: Float = (hsv.h > minHueAngle && hsv.h < maxHueAngle && hsv.s > 0.5) ? 0 : 1.0

cubeData[offset] = rgb[0] * alpha
cubeData[offset + 1] = rgb[1] * alpha
cubeData[offset + 2] = rgb[2] * alpha
cubeData[offset + 3] = alpha
offset += 4
}
}
}
let b = cubeData.withUnsafeBufferPointer { Data(buffer: $0) }
let data = b as NSData

let colorCube = CIFilter(name: "CIColorCube", withInputParameters: [
"inputCubeDimension": size,
"inputCubeData": data
])
return colorCube!
}

然后让你的过滤器调用

让 chromaKeyFilter = colorCubeFilterForChromaKey(hueAngle: 120)

我为你的标准绿屏使用了 120。

关于ios - 让 CIColorCube 过滤器在 Swift 中工作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27695134/

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