swift - 如何从父 iOS 应用程序打开 watch 应用程序？

Question

我需要从我的父级 iOS 应用打开我的 watch 扩展程序。我在 Nike+ Run Club 应用程序中看到了类似的功能。即，当用户点击父应用程序中的开始按钮时，将立即打开 watch 套件扩展。

Answer 1

正如@abjurato 所说，您只能在“锻炼模式”下启动它

import HealthKit
import WatchConnectivity
let healthStore = HKHealthStore()

func startWatchApp() {
    print("method called to open app ")

    getActiveWCSession { (wcSession) in
        print(wcSession.isComplicationEnabled, wcSession.isPaired)
        if wcSession.activationState == .activated && wcSession.isWatchAppInstalled {
            print("starting watch app")

            self.healthStore.startWatchApp(with: self.configuration, completion: { (success, error) in
                // Handle errors
            })
        }

        else{
            print("watch not active or not installed")
        }
    }

}

 func getActiveWCSession(completion: @escaping (WCSession)->Void) {
    guard WCSession.isSupported() else { return }

    let wcSession = WCSession.default()
    wcSession.delegate = self

    if wcSession.activationState == .activated {
        completion(wcSession)
    } else {
        wcSession.activate()
        wcSessionActivationCompletion = completion
    }
}