java - 在 Java 中为自定义检查异常编写 JUnit 测试用例？

Question

我正在为我的类编写一个测试用例，该用例具有抛出异常的方法(检查异常和运行时异常)。我已经按照此 link. 中的建议尝试了不同的可能测试方法.看起来它们似乎只适用于运行时异常。对于已检查的异常，我需要执行 try/catch/assert，如下面的代码所示。有没有其他方法可以尝试/捕获/断言/。您会注意到 testmethod2() 和 testmethod2_1() 显示编译错误，但 testmethod2_2() 不显示使用 try/catch 的编译错误。

class MyException extends Exception {

    public MyException(String message){
        super(message);
    }
}


public class UsualStuff {

    public void method1(int i) throws IllegalArgumentException{
        if (i<0)
           throw new IllegalArgumentException("value cannot be negative");
        System.out.println("The positive value is " + i );
    }

    public void method2(int i) throws MyException {
        if (i<10)
            throw new MyException("value is less than 10");
        System.out.println("The value is "+ i);
    }

    }

测试类:

import static org.junit.Assert.*;

import org.junit.Before;
import org.junit.Rule;
import org.junit.Test;
import org.junit.rules.ExpectedException;


public class UsualStuffTest {

    private UsualStuff u;

    @Before
    public void setUp() throws Exception {
        u = new UsualStuff();
    }

    @Rule
    public ExpectedException exception = ExpectedException.none();

    @Test(expected = IllegalArgumentException.class)
    public void testMethod1() {
        u.method1(-1);
    }

    @Test(expected = MyException.class)
    public void testMethod2() {
        u.method2(9);
    }

    @Test
    public void testMethod2_1(){
        exception.expect(MyException.class);
        u.method2(3);
    }

    public void testMethod2_3(){
        try {
            u.method2(5);
        } catch (MyException e) {
            assertEquals(e.getMessage(), "value is less than 10") ;
        }
    }
}

Answer 1

@Test(expected = MyException.class)
public void testMethod2() throws MyException {
    u.method2(9);
}