ios - 如何在快速编程中解决这个 EXC_BAD_ACCESS(code=EXC_i386_GPFLT)

Question

这是我的代码。获取此 EXC_BAD_ACCESS(code=EXC_i386_GPFLT)。我不知道如何找到并解决问题，请帮助我...应用程序在获取经度时崩溃

mapServerRequest="Hyderabad,india"
var mapAddress:NSString=mapServerRequest
mapAddress.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLPathAllowedCharacterSet())
     println(mapAddress)
var urlpath=NSString(format: "http://maps.googleapis.com/maps/api/geocode/json?address=%@", mapAddress)
     println(urlpath)
var url = NSURL.URLWithString(urlpath)
    println(url)
var jsonData:NSData=NSData(contentsOfURL:url)

       if(jsonData != nil)
    {
        var error:NSError=NSError(coder: nil)
        var result:NSDictionary=NSJSONSerialization .JSONObjectWithData(jsonData, options: NSJSONReadingOptions.MutableContainers, error: nil) as NSDictionary
        //println(result)
        if (error != nil)
        {
            mapServerResultArray=result.valueForKey("results") as NSMutableArray
           // println(mapServerResultArray)

        }
      var longitud:NSString

           longitud=mapServerResultArray.objectAtIndex(0).valueForKey("geometry").valueForKey("location").valueForKey("lng")as NSString

        var latitud :NSString = (mapServerResultArray .objectAtIndex(0).valueForKey("geometry").valueForKey("location").valueForKey("lat")) as NSString
        placeName=mapServerResultArray .objectAtIndex(0).valueForKey("formatted_address") as NSString
        var longitude:Float=longitud.floatValue
        var latitude:Float=latitud.floatValue
        self.zoomMapAndCenterAtLatitude(latitude)
        self.zoomMapAndCenterAtLongitud(longitude) 

Answer 1

简答:

在方案中启用 Zombies，它会启用一个断点，并在日志中显示正确的原因

技术原因:

你正在尝试做一些在架构中不允许的事情引用这个What's the meaning of exception code "EXC_I386_GPFLT"?