c++ - 为什么 ShellExecuteEx() 参数不起作用？

Question

假设我希望程序“C:\MyProgram.exe”以两个变量的参数运行。出现的问题是MyProgram只接收2个参数，而我明明传了3个参数。

我的代码:

SHELLEXECUTEINFO    ShExecInfo = { 0 };
CoInitializeEx(NULL, COINIT_APARTMENTTHREADED | COINIT_DISABLE_OLE1DDE);
ShExecInfo.cbSize = sizeof(SHELLEXECUTEINFO);
ShExecInfo.fMask = SEE_MASK_NOCLOSEPROCESS;
ShExecInfo.hwnd = NULL;
ShExecInfo.lpVerb = NULL;
ShExecInfo.lpDirectory = NULL;
ShExecInfo.nShow = SW_SHOW;
ShExecInfo.hInstApp = NULL;

ShExecInfo.lpFile = T("\"C:\\MyProgram.exe\"");
ShExecInfo.lpParameters = _T("\"\"") _T(" ") + dir + file[i] + _T(" ") + dir + outputfile + _T(".TIFF");
ShellExecuteEx(&ShExecInfo);
WaitForSingleObject(ShExecInfo.hProcess, 1500);
if(GetExitCodeProcess(ShExecInfo.hProcess, &exitCode)){
    MessageBox(_T("Conversion ") + file[i] + _T(" unsuccesful."), _T("TEST!"), MB_OK);
    succes = 0;
}

因为 Internet 上关于 ShellExecuteEx 的可变参数的信息不多，我找不到对此的正确解释。

你们中有人知道如何解决这个问题吗？提前致谢!

Answer 1

仅仅是因为你的构造产生了一个临时对象并且存储了指向它的指针(我猜是一个 CString)，但是当你启动程序时临时对象已经被销毁了。

auto str = _T("\"\"") _T(" ") + dir + file[i] + _T(" ") + dir + outputfile + _T(".TIFF");
ShExecInfo.lpParameters = str;
ShellExecuteEx(&ShExecInfo);