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c++ - 为什么这个实现的二进制搜索比 std::binary_search() 慢得多?

转载 作者:搜寻专家 更新时间:2023-10-31 02:21:33 25 4
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在我检测到 std::upper_bound 之前,我实现了我自己的 binarySearch 版本来确定所需元素的索引。该实现有效,但与线性搜索相比,我的 binarySearch 只快了一点点。随着搜索区域的扩大,我的实现与标准库之间的因素也会增加。

为了进行快速自测,我在本文末尾插入了完整代码。在这里快速浏览一下我的 searchBinary 实现:

template<typename T> T searchBinary(const std::vector<std::vector<T> > vectorList, const std::vector<T> compareVector) {
long iteration = 0;
size_t leftIndex = 0;
size_t rightIndex = vectorList.size()-1;
size_t pos;

while (leftIndex <= rightIndex) {
iteration++;
pos = (leftIndex + rightIndex) / 2;

if (compareVector < vectorList[pos]) {
rightIndex = pos - 1;
} else if (compareVector > vectorList[pos]) {
leftIndex = pos + 1;
} else {
cout << "Match at binary search after " << iteration << " iterations.\n";
return pos;
}
}

cout << "No match at binary search after " << iteration << " iterations.\n";
return -1;
}

这就是我弄乱运行时的方式:

void searchBinaryOwn_messure(std::vector<std::vector<u_char> > vectorList, std::vector<u_char> compareVector) {
struct timeval begin, end;
long seconds, useconds;

if (gettimeofday(&begin,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

searchBinary(vectorList, compareVector);

if (gettimeofday(&end,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

seconds = end.tv_sec - begin.tv_sec;
useconds = end.tv_usec - begin.tv_usec;
if(useconds < 0) {
useconds += 1000000;
seconds--;
}

printf("searchBinaryOwn(): %ld sec %ld usec\n\n", seconds, useconds);
return;
}

在这里看不到任何问题。如果我用 8 000 运行这个程序 000 个元素:

  • searchLinear() 耗时约 3.7 秒
  • searchBinaryOwn() 需要大约 2.8 秒
  • searchBinaryStd() 需要 ~0,0007 秒

那么,为什么两种二进制搜索之间存在如此巨大的差异?(使用 gcc 4.8.2 编译)注意:因为“cout...”大约需要 30usec,std::binarySearch 实际上比显示的要快

完整代码如下:

#include <iostream>
#include <vector>
#include <sys/time.h>
#include <algorithm>
#include <string>
#include <stdio.h>
using namespace std;


template<typename T> T searchBinary(const std::vector<std::vector<T> > vectorList, const std::vector<T> compareVector) {
long iteration = 0;
size_t leftIndex = 0;
size_t rightIndex = vectorList.size()-1;
size_t pos;


while (leftIndex <= rightIndex) {
iteration++;
pos = (leftIndex + rightIndex) / 2;

if (compareVector < vectorList[pos]) {
rightIndex = pos - 1;
} else if (compareVector > vectorList[pos]) {
leftIndex = pos + 1;
} else {
cout << "Match at binary search after " << iteration << " iterations.\n";
return pos;
}
}

cout << "No match at binary search after " << iteration << " iterations.\n";
return -1;
}

size_t searchLinear(std::vector<std::vector<u_char> > vectorList, std::vector<u_char> compareVector) {
size_t vectorListSize = vectorList.size();
for (size_t i = 0; i < vectorListSize; i++) {
if (vectorList[i] == compareVector) {
return i;
}
}
return (size_t)-1;
}

void searchLinear_messure(std::vector<std::vector<u_char> > vectorList, std::vector<u_char> compareVector) {
struct timeval begin, end;
long seconds, useconds;

if (gettimeofday(&begin,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

//search
cout << "\nPos: " << searchLinear(vectorList, compareVector) << endl;

if (gettimeofday(&end,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

seconds = end.tv_sec - begin.tv_sec;
useconds = end.tv_usec - begin.tv_usec;
if(useconds < 0) {
useconds += 1000000;
seconds--;
}

printf("searchLinear(): %ld sec %ld usec\n\n", seconds, useconds);
return;
}

void searchBinaryStd_messure(std::vector<std::vector<u_char> > vectorList, std::vector<u_char> compareVector) {
struct timeval begin, end;
long seconds, useconds;

if (gettimeofday(&begin,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

//search
cout << "found: " << std::binary_search(vectorList.begin(), vectorList.end(), compareVector) << endl;

if (gettimeofday(&end,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

seconds = end.tv_sec - begin.tv_sec;
useconds = end.tv_usec - begin.tv_usec;
if(useconds < 0) {
useconds += 1000000;
seconds--;
}

printf("searchBinaryStd(): %ld sec %ld usec\n\n", seconds, useconds);
return;
}

void searchBinaryOwn_messure(std::vector<std::vector<u_char> > vectorList, std::vector<u_char> compareVector) {
struct timeval begin, end;
long seconds, useconds;

if (gettimeofday(&begin,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

searchBinary(vectorList, compareVector);

if (gettimeofday(&end,(struct timezone *)0)) {
fprintf(stderr, "can not get time\n");
exit(1);
}

seconds = end.tv_sec - begin.tv_sec;
useconds = end.tv_usec - begin.tv_usec;
if(useconds < 0) {
useconds += 1000000;
seconds--;
}

printf("searchBinaryOwn(): %ld sec %ld usec\n\n", seconds, useconds);
return;
}


int main() {
std::vector<u_char> compareVector;
compareVector.clear();
compareVector.push_back(0xF8);
compareVector.push_back(0xD1);
compareVector.push_back(0x11);
compareVector.push_back(0xFF);

std::vector<std::vector<u_char> > vectorList;
vectorList.clear();
std::vector<u_char> temp;
for (unsigned int i = 0; i < ((unsigned int)-1); i++) {
if (i == 8000000) {
// if (i == 15000000) {
break;
}
temp.clear();
temp.push_back(0x11);
temp.push_back(0x22);
temp.push_back(0x33);
temp.push_back(0x44);
vectorList.push_back(temp);
}

vectorList[7999999] = compareVector;

cout << "Elements in vectorList: " << vectorList.size() << endl;

searchLinear_messure(vectorList, compareVector);
searchBinaryStd_messure(vectorList, compareVector);
searchBinaryOwn_messure(vectorList, compareVector);

return 0;
}

最佳答案

  1. 将您的函数原型(prototype)更改为

template<typename T> T searchBinary(const std::vector<std::vector<T> >& vectorList, const std::vector<T>& compareVector) {

即通过常量引用而不是值传递。这将避免两个 vector 拷贝。

  1. 您可以使用单个条件测试进行重构 <每次迭代。 (您还需要更改 while 条件)。

  2. 是否 iteration需要是 long ?不能短点吗?收敛的最坏情况是什么?

第 1 点很重要。 2 非常重要,3 是微优化,在某些系统上可能根本不会产生任何影响。

关于c++ - 为什么这个实现的二进制搜索比 std::binary_search() 慢得多?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31292520/

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