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c++ - 在子类中设置变量

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我目前正在研究一个非常基础的汇编程序。汇编程序需要接收汇编指令并输出 16 位二进制指令,以供我们正在制造的计算机使用。

我的设计策略是创建一个 Command 类,它有 3 个子类。每种类型的命令都有一个:A 命令、C 命令和 L 命令。为了识别我正在使用的命令类型,我包含了一个字符串 command_type,它分别是“A”、“C”或“L”。

编辑:

我在弄清楚如何正确派生这些类时仍然遇到很多麻烦。基本上,A 和 L 命令应该有一个“符号”字符串,代表一个需要转换的整数值,而 C 命令有“dest”、“comp”和“jump”值也必须被访问,但是它们没有“符号”值。

Command.h

#include <fstream>
#include <string>

class Command {
std::string command_type = "";
protected:
void set_commandType(std::string x){command_type = x;}
public:
Command();
virtual ~Command();
std::string commandType() const {return command_type;}

};
class A_COMMAND : public Command
{
std::string symbol;
public:
A_COMMAND(std::string s);
std::string get_symbol(){return symbol;}; //Returns the symbol or decimal Xxx of the current command @Xxx or (Xxx) . Should be called only when commandType() is A_COMMAND or L_COMMAND.


};

class C_COMMAND : public Command
{
std::string comp;
std::string dest;
std::string jump;
public:
C_COMMAND(std::string s, std::string d, std::string j);
std::string get_comp(){return comp;}; //Returns the comp mnemonic in the current C-command (28 possibilities). Should be called only when commandType() is C_COMMAND.
std::string get_dest(){return dest;}; //Returns the dest mnemonic in the current C-command (8 possibilities). Should be called only when commandType() is C_COMMAND.
std::string get_jump(){return jump;}; //Returns the jump mnemonic in the current C-command (8 possibilities). Should be called only when commandType() is C_COMMAND.
};

class L_COMMAND : public Command
{
std::string symbol;
public:
L_COMMAND(std::string s);
std::string get_symbol(){return symbol;}; //Returns the symbol or decimal Xxx of the current command @Xxx or (Xxx) . Should be called only when commandType() is A_COMMAND or L_COMMAND.
};

命令.cpp

#include "Command.h"

//---------------------------------------------
//A-Command functions

Command::Command(){}

A_COMMAND::A_COMMAND(std::string s) : symbol(s)
{
set_commandType("A");
}


//---------------------------------------------
//C-Command functions

C_COMMAND::C_COMMAND(std::string c, std::string d, std::string j) : comp(c), dest(d), jump(j)
{
set_commandType("C");
}

//---------------------------------------------
//L-Command functions

L_COMMAND::L_COMMAND(std::string s) : symbol(s)
{
set_commandType("L");
}

我有一个 Parser.cpp 和 Parser.h 来处理输入并负责创建命令的双端队列:

解析器.h

#include "Command.h"
#include <vector>
#include <deque>


class Parser {
private:
std::deque<Command> commands;
public:
Parser(std::vector<std::string>);
bool hasMoreCommands() //are there more commands in the input?
{
if(commands.size() != 0)
return true;
else
return false;
}
void advance(){commands.pop_front();} //move to next command, should only work if hasMoreCommands returns false}
Command currentCommand(){return commands.front();}
std::vector<std::string> translateCommands(); //convert commands into binary strings

};

解析器.cpp

#include "Parser.h"
#include "Command.h"
#include <vector>
#include <iostream>
#include <string>
#include <unordered_map>

bool inList(std::string& str, std::vector<std::string> list) //check if a given string contains one of the elements in the comp, dest, jump vectors. if so extract string for use in constructor
{
for(auto i = list.begin(); i!=list.end(); ++i)
{
std::size_t found = str.find(*i);
if(found!=std::string::npos)
{
return true;
}
}
return false;
}


Parser::Parser(std::vector<std::string> input) {
std::vector<std::string> dest_list = {"","M","D","MD","A","AM","AD","AMD"}; //all possible dests
std::vector<std::string> comp_list = {"0","1","D","A","!D","!A","-D","-A","D+1","A+1","D-1","A-1","D+A","D-A","A-D","D&A","D|A","M","!M","-M","M+1","M-1","D+M","D-M","M-D","D&M","D|M"}; //all possible comps
std::vector<std::string> jump_list = {"","JGT","JEQ","JGE","JLT","JNE","JLE","JMP"}; //all possible jumps
std::string dest, comp, jump;
std::deque<Command> commands;
for(std::vector<std::string>::const_iterator i = input.begin(); i != input.end(); ++i)
{
std::string line = *i;
if(*line.begin()=='@') //A-command
{
A_COMMAND command(line.substr(1));
std::cout << "Command type: " << command.commandType() << "\n";
std::cout << "symbol: " << command.get_symbol() << "\n";
commands.push_back(command);
}
else if(*line.begin()=='(' && *line.rbegin() == ')' && line.size() > 2) //L-command
{
L_COMMAND command(line.substr(1, line.size() - 2));
std::cout << "Command type: " << command.commandType() << "\n";
std::cout << "symbol: " << command.get_symbol() << "\n";
commands.push_back(command); }
else
{
std::string rhs = line;
std::string dest_string = "";
std::string comp_string = "";
std::string jump_string = "";
size_t equals_pos = line.find('='); //position of = in string, if present
size_t semi_pos = line.find(';'); //position of ; in string, if present
if(equals_pos != line.npos) //if there is an = then we have a dest
{
dest_string = line.substr(0,equals_pos);
rhs = line.substr(equals_pos+1);
}
if(semi_pos != line.npos) //jump
{
comp_string = rhs.substr(0,semi_pos);
jump_string = rhs.substr(semi_pos+1);
}
else //no jump
{
comp_string = rhs;
}

//now confirm if inputs are valid
if(inList(dest_string, dest_list))
dest = dest_string;
else
std::cout << "invalid dest \n";
if(inList(comp_string, comp_list))
comp = comp_string;
else
std::cout << "invalid comp \n";
if(inList(jump_string, jump_list))
jump = jump_string;
else
std::cout << "invalid jump \n";

C_COMMAND command(comp, dest, jump);
std::cout << "Command type: " << command.commandType() << "\n";
std::cout << "dest: " << command.get_dest() << "\n";
std::cout << "comp: " << command.get_comp() << "\n";
std::cout << "jump: " << command.get_jump() << "\n";
commands.push_back(command);
}
}
}

我的 main.cpp 加载输入,并将其传递给解析器。我遇到的问题是我无法对输入做任何事情。

我试过这样写一个函数:

string translateLine(Command command, Code code) //Code is a table for translating the command
{
string output;
if(command.commandType() == "A")
{
string symbol = parser.currentCommand().get_symbol();
cout << symbol << endl;
//perform binary conversion
}
/*else if(command.commandType() == "C")
{
string dest = command.get_dest();
}*/
//shouldn't be any L commands in symbol-less version
else
{
std::cout << "unexpected command value \n";
}
return output;
}

但是当我调用 get_symbol() 时,编译器无法识别该函数。我知道这是因为基本命令没有 get_symbol() 函数,但我无法弄清楚如何正确地将函数添加到基类并将它们派生到较低的 3 个。我不能只做纯虚拟,因为并非所有功能都在每个类中使用。我怎样才能正确地做到这一点?

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