c++ - 如何从析构函数中调用成员函数

Question

我正在为一个 C++ 项目工作，但我想知道如何从析构函数中的类/结构调用成员函数。我项目的其余部分进展顺利，所以我只需要知道它就可以完成:)

    ~Drink()
    {
        cout << "hi";
        cout << "I want to know how to summon a member function from a destructor.";
    }

    int Drink::dailyReport()
    {
        cout << "This is the member function I want to call from the destructor.";
        cout << "How would I call this function from the destructor?"
    }

正确的语法和所有将不胜感激!如何从析构函数调用成员函数的示例会很可爱!

Answer 1

这里的问题是您没有为析构函数添加前缀 Drink::

由于析构函数不知道它应该与哪个类相关联(假设它是在类声明之外定义的)，它甚至不知道它有一个成员函数要调用。

尝试将您的代码重写为:

Drink::~Drink() // this is where your problem is
{
    cout << "hi";
    cout << "I want to know how to summon a member function from a destructor.";
    dailyReport(); // call the function like this
}

int Drink::dailyReport()
{
    cout << "This is the member function I want to call from the destructor.";
    cout << "How would I call this function from the destructor?"
}