c++ - 使用枚举类型c++类写一个卖爆米花和饮料的程序

Question

我的任务是:编写一个使用枚举类型销售爆米花和饮料的程序。您必须在您的程序:枚举大小 {SMALL, MEDIUM, LARGE, JUMBO};大小爆米花大小，饮料大小；你应该创建一个菜单，要求用户选择他们想要的饮料的大小，并选择什么大小的他们想要的爆米花。然后你应该打印出饮料和爆米花的总成本。

价格:爆米花小= 1.25，中= 2.25，大= 3.50，大= 4.25苏打小=1.50，中=2.50，大=3.75，大=4.50

这是我的代码:

int main()
{
    enum sizes { SMALL, MEDIUM, LARGE, JUMBO };
    sizes popcornSize, drinkSize;

    double sp=1.25, mp=2.25, lp=3.50, jp=4.25, TOTALp, TOTALs, ss=1.50,         ms=2.50, ls=3.75, js=4.50 ;
    char choice, answer, Psize, Ssize;
    int how_many;
    cout << "Hello I am selling popcorn and sodas, would you like to buy  some? type yes or no please." << endl;
    cin >> choice;
    if (choice == 'yes')
    {
        cout << "Great, what would you like popcorn or soda? Type P for popcorn and S for soda." << endl;
        cin >> answer;
        if (answer = 'P')
        {
            cout << "what size popcorn would you like (type s for small, m for medium, l for large or j for jumbo) and how many (type a single number)?" << endl;
            cin >> Psize >> how_many;
            if (Psize = 's')
            {
                TOTALp = sp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'm')
            {
                TOTALp = mp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'l')
            {
                TOTALp = lp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'j')
            {
                TOTALp = jp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }


            else if (answer = 'S')
            {

                cout << "what size soda would you like (type small, medium, large or jumbo) and how many (type a single number)?" << endl;
                cin >> Ssize >> how_many;
                if (Ssize = 's')
                {
                    TOTALs = ss*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'm')
                {
                    TOTALs = ms*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'l')
                {
                    TOTALs = ls*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'j')
                {
                    TOTALs = js*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }

            }
            cout << "Thanks for buying come again soon." << endl;
        }

        }
        else if (choice == 'no')
            cout << "Okay have a great day!" << endl;
    return 0;
}

我需要帮助在程序中实现枚举，以及如何将所有这些 if/else 语句放入 switch 结构中。此外，出于某种原因，当我在用户输入他们的选择后运行我的程序时，程序结束，我无法弄清楚为什么。

Answer 1

您的程序结束，因为选择永远不会是"is"或“否”。由于 choice 是一个字符，它只能是一个字符。将"is"更改为“y”，将“否”更改为“n”，它应该可以工作。

我将举例说明如何编写 switch 语句，以便您可以根据其余代码调整它。

#include "stdio.h"
#include "iostream"

using namespace std;

int main()
{
    enum sizes { SMALL, MEDIUM, LARGE, JUMBO };
    sizes popcornSize, drinkSize;

    double sp=1.25, mp=2.25, lp=3.50, jp=4.25, TOTALp, TOTALs, ss=1.50,         ms=2.50, ls=3.75, js=4.50 ;
    char choice, answer, Psize, Ssize;
    int how_many;
    cout << "Hello I am selling popcorn and sodas, would you like to buy  some? type yes or no please." << endl;
    cin >> choice;
    switch(choice)
    {
    case 'y':
        cout << "Great, what would you like popcorn or soda? Type P for popcorn and S for soda." << endl;
        cin >> answer;
        if (answer = 'P')
        {
            cout << "what size popcorn would you like (type s for small, m for medium, l for large or j for jumbo) and how many (type a single number)?" << endl;
            cin >> Psize >> how_many;
            if (Psize = 's')
            {
                TOTALp = sp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'm')
            {
                TOTALp = mp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'l')
            {
                TOTALp = lp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }
            else if (Psize = 'j')
            {
                TOTALp = jp*how_many;
                cout << "Okay you total is: " << TOTALp << endl;
            }


            else if (answer = 'S')
            {

                cout << "what size soda would you like (type small, medium, large or jumbo) and how many (type a single number)?" << endl;
                cin >> Ssize >> how_many;
                if (Ssize = 's')
                {
                    TOTALs = ss*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'm')
                {
                    TOTALs = ms*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'l')
                {
                    TOTALs = ls*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }
                else if (Ssize = 'j')
                {
                    TOTALs = js*how_many;
                    cout << "Okay you total is: " << TOTALs << endl;
                }

            }
            cout << "Thanks for buying come again soon." << endl;
        }
    break;
    case 'n':
        cout << "Okay have a great day!" << endl;
    break;
    default:
        cout << "I dont understand...!" << endl;
    break;
    }
    return 0;
}