c++ - 这段代码有什么问题？斐波那契数列

Question

它应该打印斐波那契数列直到一个位置，但它只打印 1 1 2，即使我要求的不仅仅是前三个元素。我该如何解决这个问题？

#include <iostream>
using std::cout;
using std::cin;

int main()
{
    cout << "Enter a number: ";
    int number;
    cin >> number;
    int count = 1;
    int a = 1;                  //The first number of the Fibonacci's serie is 1
    int b = 1;                  //The second number of the Fibonacci's serie is 2
    while (count <= number)
    {
        if (count < 3)
            cout << "1 ";
        else
        {
            number = a + b;     //Every number is the sum of the previous two
            cout << number << " ";
            if (count % 2 == 1)
                a = number;
            else
                b = number;
        }
        count++;
    }

    return 0;
}

Answer 1

您在这里使用 number 作为循环迭代的最大次数:

while (count <= number)

但是在循环内，您使用与当前 Fib 值相同的变量来为每次迭代输出。

number = a + b;     //Every number is the sum of the previous two
cout << number << " ";

这导致循环提前终止。您需要为这两个不同的值选择不同的变量名称。