c++ - 如何在不阻塞主窗体的情况下创建对话框？

Question

现在我可以做:

void MainWindow::on_actionPATH_triggered() {
    std::unique_ptr<QDialog> win(new QDialog());
    win->exec();
}

我应该使用 async/在单独的线程中运行以避免阻塞主窗口，还是有办法订阅以关闭甚至删除/释放那里的对象？

Answer 1

你可以只使用show()

void MainWindow::on_actionPATH_triggered() {
    QDialog* win = new QDialog();
    //needed connect
    win->setAttribute(Qt::WA_DeleteOnClose);//we don't want memory leak
    win->show();
}

和使用

win->setModal(false);//but it is default option, you don't need to change it

来自 doc :

By default, this property is false and show() pops up the dialog as modeless. Setting his property to true is equivalent to setting QWidget::windowModality to Qt::ApplicationModal. exec() ignores the value of this property and always pops up the dialog as modal.

Qt::WA_DeleteOnClose 将在用户关闭对话框时删除它。

您还可以将父级设置为对话框:

QDialog* win = new QDialog(this);

在这种情况下，win 将与您的主窗口一起删除。

Info about Qt parent child relationship

而且你不需要在这里单独的线程。