c++ - 如何将字符串转换为const char

Question

所以我解决了第一个问题。我运行代码并提示我在数组中输入一些列表。输入列表后，我将此函数作为 search_func 运行。但它一直返回未找到记录。是因为 [0] 吗，奇怪，因为我在 for 循环中有它。

请帮忙。 book books[] 是一个类对象..

int search(book books[], char search) {
    const char* boook =books[0].gettitle();
  //......try this but it failed please help
  cout << "Search books by title:____  ";

  cin >> search;

  bool yes = false;
  int size=2;

  for(int index=0; index<size; index++) {
    if(strcmp(boook,search) == 0 )//....error at this line
         { 
        found = true;
        cout<<"book found "<<endl;
        //cout<<"Author Name: "<<fn<<" "<<ln<<endl;
        break;
      }
  }

  if(!yes)
    cout<<"no book found"<<endl;
}

Answer 1

试试这个:

const char* c_str = books[0].gettitle().c_str();

http://www.cplusplus.com/reference/string/string/c_str/

编辑:

如果 gettitle() 返回一个临时的，那么上面的方法将不起作用。您将需要这样做:

string title = books[0].gettitle();
const char* c_str = title.c_str();