c++ - 程序由于某种原因挂起

Question

以下代码应该从输入中读取记录并将它们存储在名为 file.dat 的文件中。然后它应该按升序排列这些记录，但由于某种原因程序在第二个 while 循环中挂起在行“file1.seekg(-(sizeof(r)),std::ios::cur);”。谁能告诉我哪里出了问题？

#include <iostream>
#include <fstream>
#include <strstream>

int main()
{
std::ofstream file;
file.open("file.dat",std::ios::trunc|std::ios::binary);
if(!file)
    std::cout<<"unable to open for output";

struct record
{
    char code[6];
    char name[20];
    int i;
};

record r;
int a = 0;

while(1)
{
    std::cout<<"Record " << a + 1 << std::endl;
    std::cout<<"Enter character code, name and an int \n";
    std::cin.ignore();
    std::cin.getline(r.code,6);
    std::cin.getline(r.name,20);
    std::cin>>r.i;
    file.write((char *)&r,sizeof(r));
    std::cout<<"\nAdd another (y\\n) : ";
    char c;
    std::cin>>c;
    if(c == 'n')
        break;
    a++;
    std::cout<<'\n'<<'\n';
}
file.close();

std::fstream file1("file.dat",std::ios::in|std::ios::out|std::ios::binary);
if(!file1)
    std::cout<<"unable to open file1";

else
{
    if(a>0)
    {   while(a)
        {
            file1.seekp(0);
            for(int i = a; i>0;i--)
            {
                record r1;
                file1.read((char *)&r,sizeof(r));
                file1.read((char *)&r1,sizeof(r1));
                if(r1.i < r.i)
                {
                    file1.seekp(-(sizeof(r)*2),std::ios::cur);
                    file1.write((char *)&r1,sizeof(r));
                    file1.write((char *)&r,sizeof(r));
                    file1.seekg(-(sizeof(r)),std::ios::cur);
                }
            }

            a--;
        }
    }
    file1.close();
}

std::ifstream file2("file.dat",std::ios::binary);
if(!file2)
    std::cout<<"unable to open file2";
  else
while(1)
{
    std::cout<<"\n\n";
    file2.read((char *)&r,sizeof(r));
    if(file2.eof())
        break;
    std::cout<<r.code<<'\t'<<r.name<<'\t'<<r.i;
}
}

Answer 1

首先

更改 std::get.ignore -> std::cin.ignore()

如果你想丢弃一个字符。

它编译得很好并创建了 file.dat 文件..

虽然你可以检查 file.dat 中的记录