c++ - 生成具有定义数据类型的随机数

Question

我想生成一个很长的整数随机数，我希望它是 224 位随机数。但我能找到的最长数据类型是 unsigned long long，它是 64 位。首先我这样做了:

#include <iostream>
#include <string>
#include <stdint.h>
#include <stdlib.h>
#include <ctime>
#include "random.h"
int main()
{
    srand(time(0));

    unsigned long long num1 = rand();
    unsigned long long num2 = rand();

    cout<<"1st random number = " << num1 << endl;
    cout<<"2nd random number = " << num2 << endl;

    return 0;
}

我的想法是定义 224 位整数的新数据类型。所以我尝试制作新的 random.h 文件:

class int224 
{
    unsigned int data[7];
}

然后修改第一段代码:

#include <iostream>
#include <string>
#include <stdint.h>
#include <stdlib.h>
#include <ctime>
#include "random.h"
int main()
{
    srand(time(0));

    int224 num1 = rand();
    int224 num2 = rand();

    cout<<"1st random number = " << num1 << endl;
    cout<<"2nd random number = " << num2 << endl;

    return 0;
}

但是它返回了错误，也许我在定义新数据类型时犯了一个错误，我很感激任何帮助。谢谢。

Answer 1

我想到了以下，不确定这是否适合你

#include <iostream>
#include <chrono>
#include <random>

struct int224 
{
    unsigned int data[7];

    int224 operator+(int224);
    int224 operator-(int224);

    int224 ()
    {
     unsigned seed =
         std::chrono::system_clock::now().time_since_epoch().count();

        std::minstd_rand0 mygen (seed); 

      for(auto i=0;i<7;i++)
        data[i]=mygen();    
    }

    friend std::ostream& operator<<(std::ostream&, const int224&);
};

std::ostream& operator<<(std::ostream& os, const int224& r)
{
    for(auto i=0;i<7;i++)
        os<<r.data[i];
    return os;
}

int main ()
{

  int224 r;
  std::cout<<r<<std::endl;

  int224 j;
  std::cout<<j;

  return 0;
}