c++ - 重新分配分离的 boost::thread 是否安全

Question

例如

boost::thread th = boost::thread(a_lengthy_function);
th.detach();
th = boost::thread(another_function);

第一个线程是否会被第二个线程取消或影响？

Answer 1

来自 boost doc :

A thread can be detached by explicitly invoking the detach() member function on the boost::thread object. In this case, the boost::thread object ceases to represent the now-detached thread, and instead represents Not-a-Thread.

thread() noexcept;Effects:Constructs a boost::thread instance that refers to Not-a-Thread

所以分离的线程与默认构造的线程是一样的。所以，是的，您可以安全地移动分配给默认构造的线程，而您的第二个问题的答案是否定的，这两个线程完全不相关。

仅供引用，这同样适用于 std::thread ...