c++ - 编译错误 : "pointer can only be subtracted from another pointer"

Question

刚刚学习 C++，我很享受我的第一个程序 它并不多，它只是解决了数学问题 据我所知我的逻辑是距离公式有一些问题右 sqrt((x2-x1)+(y2-y1))。但是我收到错误

error C2113: '-' : pointer can only be subtracted from another pointer which is throwing me off.

奖金问题...如果有人能告诉我一种方法，可以在用户完成先前的选择后将其引导回第一个菜单，那会很酷。我假设有某种循环，但我还没有在我的 C++ 类(class)中介绍它。

这是代码(抱歉，如果它乱七八糟，但我还没有学会正确的格式)

#include "stdafx.h"
#include <iostream>
#include <cstdlib>
#include <cmath>
using namespace std;


int selection;
int choice;
int choice2;
double height;
double length;
double a;
double x;
double y;
double const pi = 3.14;
double r;
double m;
double x1;
double x2;
double y1;
double y2;
double distance;

int main(){
cout<<"-------------------------"<<endl;
cout<<"     MATH DESTROYER      "<<endl;
cout<<"-------------------------"<<endl;
cout<<"  1-Geometry Solver      "<<endl;
cout<<"  2-Algebra Solver       "<<endl;
cout<<"  3-"<<endl;
cout<<endl;
cout<<"  Select Option number:  "<<endl;
cin>>selection;
cout<<endl;
cout<<endl;
    switch(selection){
    case 1:
    cout<<"-------------------------"<<endl;
    cout<<"     GEOMETRY SOLVER     ";cout<<endl;
    cout<<endl;
    cout<<" 1-Perimeter of a square "<<endl;
    cout<<" 2-Area of a square      "<<endl;
    cout<<" 3-Perimeter of a rectangle"<<endl;
    cout<<" 4-Area of a rectangle   "<<endl;
    cout<<" 5-Perimeter of a circle "<<endl;
    cout<<" 6-Area of a circle      "<<endl;
    cout<<" Select Option number:   "<<endl;
    cout<<"-------------------------"<<endl;
    cin>>choice;
    cout<<endl;
    cout<<endl;
    switch(choice){
            case 1:
                cout<<"-------------------------"<<endl;
                cout<<"  PERIMITER OF A SQUARE  "<<endl;
                cout<<endl;
                cout<<"Enter Height"<<endl;
                cin>>height;
                cout<<"Enter Length"<<endl;
                cin>>length;
                cout<<"Perimiter of Square ="<<(height*2)+(length*2)<<endl;
                cout<<"-------------------------"<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

            case 2:
                cout<<"AREA OF A SQUARE"<<endl;
                cout<<endl;
                cout<<"Enter Length"<<endl;
                cin>>length;
                cout<<endl;
                cout<<endl;
                cout<<"FORMULA L^2";
                cout<<endl;
                cout<<endl;
                cout<<"AREA of Square ="<<pow(length,2)<<endl;//(pow)(length,2)= length to the power of 2 or lenght^2
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

            case 3:
                cout<<"PERIMITER OF A RECTANGLE"<<endl;
                cout<<endl;
                cout<<"Enter Height"<<endl;
                cin>>height;
                cout<<"Enter Length"<<endl;
                cin>>length;
                cout<<endl;
                cout<<endl;
                cout<"FORMULA L2+H2";
                cout<<endl;
                cout<<endl;
                cout<<"Perimiter of Rectangle ="<<(height*2)+(length*2)<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

            case 4:
                cout<<"AREA OF A RECTANGLE"<<endl;
                cout<<endl;
                cout<<"Enter Height"<<endl;
                cin>>height;
                cout<<"Enter Length"<<endl;
                cin>>length;
                cout<<endl;
                cout<<endl;
                cout<"FORMULA L2+H2";
                cout<<endl;
                cout<<endl;
                cout<<"Perimiter of Rectangle ="   <<height*length<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

                case 5:
                cout<<"PERIMITER OF A CIRCLE"<<endl;
                cout<<endl;
                cout<<"Enter Radius"<<endl;
                cin>>r;
                cout<<endl;
                cout<<endl;
                cout<<"FORMULA peremiter=PI X D";
                cout<<endl;
                cout<<endl;
                cout<<"Perimiter of circle ="<<pi*(r*2)<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

                case 6:
                cout<<"AREA OF A CIRCLE"<<endl;
                cout<<endl;
                cout<<"Enter Radius"<<endl;
                cin>>r;
                cout<<endl;
                cout<<endl;
                cout<<"FORMULA PI X R^2";
                cout<<endl;
                cout<<endl;
                cout<<"Area of Circle ="<<pi*(pow(r,2))<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

    }
    case 2:
    cout<<"      ALGEBRA MASTER     "
    cout<<"-------------------------"<<endl;
    cout<<"    1-Distance Formula   "<<endl;
    cout<<"    2-Slope              "<<endl;
    cout<<"    3-Pythagorean Theorm "<<endl;
    cout<<"-------------------------"<<endl;
    cout<<endl;
    cout<<"Select Option number:"<<endl;
    cin>>choice2;
        switch(choice2){
            case 1:
                cout<<"Distance Formula"<<endl;
                cout<<endl;
                cout<<"Enter first y point (y1)"<<endl;
                cin>>y1;
                cout<<endl;
                cout<<"Enter second y point (y2)"<<endl;
                cin>>y2;
                cout<<endl;
                cout<<"Enter first x point (x1)"<<endl;
                cin>>x1;
                cout<<endl;
                cout<<"Enter second x point (x2)"<<endl;
                cin>>x2;
                cout<<"D=sqrt (x2-x1)+(y2-y1)";
                cout<<endl;
                cout<<endl;
                cout<<"Distance ="<<sqrt((x2-x1)+(y2-y1))<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

                case 2:
                cout<<"AREA OF A CIRCLE"<<endl;
                cout<<endl;
                cout<<"Enter Radius"<<endl;
                cin>>r;
                cout<<endl;
                cout<<endl;
                cout<<"FORMULA PI X R^2";
                cout<<endl;
                cout<<endl;
                cout<<"Area of Circle ="<<pi*(pow(r,2))<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

                case 3:
                cout<<"AREA OF A CIRCLE"<<endl;
                cout<<endl;
                cout<<"Enter Radius"<<endl;
                cin>>r;
                cout<<endl;
                cout<<endl;
                cout<<"FORMULA PI X R^2";
                cout<<endl;
                cout<<endl;
                cout<<"Area of Circle ="<<pi*(pow(r,2))<<endl;
                cout<<endl;
                cout<<endl;

                system("pause");
                return 0;

    }


    }
}

Answer 1

更新:

看起来像y0 , y1和 yn是specified as part of POSIX这可以解释为什么您不会在 C 或 C++ 标准中找到此文档:

The y0(), y1(), and yn() functions shall compute Bessel functions of x of the second kind of orders 0, 1, and n, respectively.

全局命名空间污染的解决方案是 declare your variables in your own namespace .

原创:

你有 <代替 <<在你的一些cout调用，例如这里:

cout<"FORMULA L2+H2";
    ^

应该是:

cout<<"FORMULA L2+H2";
    ^^

也在 clang 中和 gcc , 我与你的全局冲突 y1和全局 y1来自 cmath header ，这使得:

cout<<"Distance ="<<sqrt((x2-x1)+(y2-y1))<<endl;
                                     ^^

还有其他几行中断，我的解决方案是重命名 y1但更好的解决方案是不使用全局变量。