java - 像java short []一样在c中创建short int数组

Question

Java:

byte[] arr1=new byte[]{0x01};
String aa = "helloo";
short[] s1 = new short[1]; // **
s1[0] = 246;               // **

Object[] obj = new Object[]{s1,arr1,aa}

C:

signed char a1[] = {0x01};
char *str = "helloo";
short int st1[] = {246}; // **

char*  c [] = {st1,str1,c2};

short int st1[] = {246} 是否正确？我收到此错误:
“从‘short *’到‘char *’的非法隐式转换”。如何将 short 赋值给 char？

Answer 1

char*  c []

是指针数组，不是字符数组。

使用类似的东西

short st1[] = { 246 };
char* str = "helloo";
char  c [] = {st1[0], str[0], str[1], str[2], str[3], str[4], str[5]};

str[i] 获取单个字符，因为“char* str”指向数组的第一个元素。

如果你需要一个字符串数组，那就制作它

char tmp[1024];
// itoa is the conversion of st1[0] to string
char* c[] = { itoa(st1[0], tmp, 10), str };