c++ - 当我们在 C++ 的参数中传递它们时，如何修改一些数组而不修改其他数组？

Question

我有以下 C++ 代码。当我们通过函数 modify 传递它时，我可以修改数组 x[] 的内容，但我不希望数组 z 的内容在我们传递它时被修改。我在尝试这样做时遇到了几个错误。请问你能帮帮我吗？看来我在函数中对矩阵 m 的初始化也有错误。

#include<iostream>
using namespace std;
void modify(int y[], int f[], const int size)
{
    int m[size];
    for (int i = 0; i < size; i++)
    {
        m[i] = f[i];
    }
    for (int i = 0; i <= 5; i++)
    {
        y[i] = 2 * y[i];
        m[i] = 2 * m[i];
        cout << "y[" << i << "]=" << y[i] << "\t"<<endl;
        cout << "m[" << i << "]=" << m[i] << "\t"<<endl;
    }
    cout << endl;
}
int main(){
    int x[6] = {1,2,3,4,5,6};
    int z[6] = {1,2,3,4,5,6};
    for (int i = 0; i <= 5; i++)
    {   cout << "x[" << i << "]=" << x[i]<<"\t"<<endl;
        cout << "z[" << i << "]=" << z[i] << "\t"<<endl;
    }
    cout << endl;
    modify(x,z,6);
    for (int i = 0; i <= 5; i++)
    {
        cout << "x[" << i << "]=" << x[i] << "\t" << endl;
        cout << "z[" << i << "]=" << z[i] << "\t" << endl;
    }
    cout << endl;
    system("pause");
    return 0;
}

Answer 1

将modify的参数f设为const int数组。这样，就不能对f的内容进行任何修改。

void modify(int y[], const int f[], const int size)